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labwork [276]
3 years ago
7

What is an essential characteristic of an object in equilibrium

Physics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

The essential characteristics of an object in equilibrium is acceleration of the object must  be zero.

Explanation:

Equilibrium: An object acted upon by several forces is said to be in equilibrium if it does no it moves or rotate. Equilibrium can be defined as the state of stability of an object.

Condition for equilibrium

(i) The resultant force acting on the object must me equal to zero.

(ii) The sum of moment acting on the object must be equal to zero.

But.

F = ma..................... Equation 1

Where F =  net force , m = mass, a = acceleration.

from the equation above,

For  F = 0 N, a must be equal to zero.

<em>From the above, the essential characteristics of an object in equilibrium is acceleration must be zero</em>

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Naddika [18.5K]

Answer:

the rate of acceleration of the train is 4 m/s²

Explanation:

Given;

initial velocity of the train, u = 10 m/s

change in time of motion, dt = 5 s

final velocity of the train, v = 30 m/s

The rate of acceleration of the train is calculated as;

a = \frac{dv}{dt} = \frac{v-u}{dt} = \frac{30-10}{5} = \frac{20}{5} = 4 \ m/s^2

Therefore, the rate of acceleration of the train is 4 m/s²

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Why dont animal cells need chloroplasts?
Zigmanuir [339]
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During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshi
vladimir2022 [97]

Answer:

At a deceleration of 60g, or 60 times the acceleration due to gravity a person will travel a distance of 0.38 m before coing to a complete stop

Explanation:

The maximum acceleration of the airbag = 60 g, and the duration of the acceleration = 36 ms or 36/1000 s or 0.036 s

To find out how far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60g

we write out the equation of motion thus.

S = ut + 0.5at²

wgere

S = distance to come to complete stop

u = final velocoty = 0 m/s

a = acceleration = 60g = 60 × 9.81

t = time = 36 ms

as can be seen, the above equation calls up the given variable as a function of the required variable thus

S = 0×0.036 + 0.5×60×9.81×0.036² = 0.38 m

At 60g, a person will travel a distance of 0.38 m before coing to a complete stop

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A commonly used unit of electrical energy.
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A block with mass 0.5 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.2 m. W
lianna [129]

Answer:

So coefficient of kinetic friction will be equal to 0.4081

Explanation:

We have given mass of the block m = 0.5 kg

The spring is compressed by length x = 0.2 m

Spring constant of the sprig k = 100 N/m

Blocks moves a horizontal distance of s = 1 m

Work done in stretching the spring is equal to W=\frac{1}{2}kx^2=\frac{1}{2}\times 100\times 0.2^2=2J

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