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3 years ago

Where dose the heat for geothermal energy come from?

Physics

2 answers:

madreJ [45]3 years ago

8 0

Heat used for geothermal energy comes from molten rock, called magma. i hope it helps :)

Cloud [144]3 years ago

5 0

Answer:

from steam produced by the earth

Explanation:

apex

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The place you get your hair cut has two nearly parallel mirrors 6.5 m apart. As you sit in the chair, your head is

Ghella [55]

Complete question is;

The place you get your hair cut has two nearly parallel mirrors 6.50 m apart. As you sit in the chair, your head is 3.00 m from the nearer mirror. Looking toward this mirror, you first see your face and then, farther away, the back of your head. (The mirrors need to be slightly nonparallel for you to be able to see the back of your head, but you can treat them as parallel in this problem.) How far away does the back of your head appear to be?

Answer:

13 m

Explanation:

We are given;

Distance between two nearly parallel mirrors; d = 6.5 m

Distance between the face and the nearer mirror; x = 3 m

Thus, the distance between the back-head and the mirror = 6.5 - 3 = 3.5m

Now, From the given values above and using the law of reflection, we can find the distance of the first reflection of the back of the head of the person in the rear mirror.

Thus;

Distance of the first reflection of the back of the head in the rear mirror from the object head is;

y' = 2y

y' = 2 × 3.5

y' = 7

The total distance of this image from the front mirror would be calculated as;

z = y' + x

z = 7 + 3

z = 10

Finally, the second reflection of this image will be 10 meters inside in the front mirror.

Thus, the total distance of the image of the back of the head in the front mirror from the person will be:

T.D = x + z

T.D = 3 + 10

T.D = 13m

8 0

4 years ago

A transmission line consisting of two concentric circular cylinders of metal, with radii a, and b, with b > a, is filled with

AURORKA [14]

Answer:

P = √( μ / ε ) × πa^2 |Jo|^2 ln {b/a}.

Explanation:

So, we will be making use of the data or parameters given in the question above;

=>" radii a, and b, with b > a, is filled with a uniform dielectric material with permittivity ε and permeability μ0."

=> " A TEM mode is propagated along the line and the peak value of magnetic field when rho = a is B0."

So, we will be making use of the two equations below;

Ë = ( λ/ 2πEP) × P'. --------------------------(1)..

B' = √ μE × ( λ/ 2πEP) × P' --------------(2).

Where equation (1) and (2) represent Gauss' law and magnetic field equation respectively.

Jo = 1/√ μE × λ/2 × π × a.

When we solve for charge per unit length, we have;

λ = 2 × π × Jo × a × √ μE.

The energy flux,s = E' × J'= √μE× |Jo(Z) |^2 × a^2/b^2 { cos^2 kz - wt + Avg Jo} Z'.

Hence, the time. Average power flux = 1/2× √ μE× |Jo(Z) |^2 × a^2/b^2 × Z'.

Therefore, P = ∫z' . <s> da

P = ∫ ∫ 1/2× √ μE× |Jo(Z) |^2 × a^2/b^2 × Z' pd pd p Θ.

(Take limit on the first at second integration as : 2π,0 and b,a).

P = √( μ / ε ) × πa^2 |Jo|^2 ln {b/a}.

5 0

3 years ago

Which of the following did Christian Doppler explain? A. Atmospheric changes that affect climate B. The transfer of electricity

sergejj [24]

C is the best answer

4 0

3 years ago

Read 2 more answers

You drop a single coffee filter of mass 1.5 grams from a very tall building, and it takes 49 seconds to reach the ground. In a s

Tresset [83]

(a) 0.0147 N

When the filter reaches the terminal speed, it means that its acceleration is now zero, so the net force acting on it is zero.

There are only two forces acting on the filter:

- The weight of the filter, downward: W = mg, where

$m=1.5 g = 0.0015 kg$ is the mass of the filter

$g=9.8 m/s^2$ is the acceleration due to gravity

- The air resistance, upward, $F_a$

Since the net force is zero, we have

$W-F_a =0$

and solving the equation we find the upward force of air resistance:

$F_a=W=mg=(0.0015kg)(9.8 m/s^2)=0.0147 N$

(b) 0.0441 N

The problem is exactly identical to before, but this time the mass of the stack of filters is 3 times the mass of the single filter, so

$m=3 (0.0015 kg)=0.0045 kg$

And so, the upward force of air resistance is

$F_a = mg=(0.0045 kg)(9.8 m/s^2)=0.0441 N$

(c) 28.3 s

We know that the single coffee filter takes t=49 s to reach the ground, travelling at constant terminal speed of v, so the distance covered (the height of the building) is

$d=vt$

where t = 49 s.

We also know that the air resistance is proportional to the square of the terminal speed:

$F_{air} \propto v^2$

which means

$v\propto \sqrt{F_{air}}$

For the stack of three filters, we found (b) that the air resistance is 3 times the air resistance for the single filter (a). Therefore, the terminal speed of the stack of filter will be $\sqrt{3}$ times larger than the terminal speed of the single filter.

Therefore, the time taken will be:

$t'=\frac{d}{v'}=\frac{d}{\sqrt{3} v}=\frac{t}{\sqrt{3}}$

And since t = 49 s, we have

$t'=\frac{49 s}{\sqrt{3}}=28.3 s$

8 0

3 years ago

A school bus drives north and then east through the city as it takes students to school. The bus crosses a city block every 10 s

Alona [7]

Answer:

The bus is moving at a constant speed.

Explanation:

We have the following facts from the question;

- The bus crosses a city block every 10 seconds.

- all the city blocks are the same length

Since all the city block are the same length, let's say the distance is d.

Since it crosses the city block every 10 seconds, we know that;

Speed = distance/time

Thus, Speed = d/10

Thus,it is moving at this speed of d/10 all through.

Therefore we can conclude that the bus is moving at a constant speed.

7 0

3 years ago