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kkurt [141]
4 years ago
10

the best player on a basketball team makes 75% of all free throws. The second best makes 70% of all free throws, and the third-b

est player makes 65% of all free throws. Based on their experimental probabilities, estimate the number of free throws each player will make in his or her next 40 attempts. Explain
Mathematics
1 answer:
weeeeeb [17]4 years ago
7 0

Answer:

Best Player: 30

Second Best: 28

Third Best: 26

Step-by-step explanation:

1) Break the percents down into smaller increments - 5% for example.

2) 5% or 1/20 of 40 (the whole) is 2.

3) Using this knowledge, we know that a player who makes 5% of his throws makes 2 shots.

4) 75% is made up of 15 groups of 5%, so that means if you multiply 15 by 2 (the number of shots made for every group of 5%), then you get 30.

5) 70% is made up of 14 groups of 5%, so that means if you multiply 14 by 2 (the number of shots made for every group of 5%), then you get 28.

6) 65% is made up of 13 groups of 5%, so that means if you multiply 13 by 2 (the number of shots made for every group of 5%), then you get 26.

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Step-by-step explanation:

(b) If F_G = m_1g, then

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Note that m_1 cancel out so we get

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m_2 = \dfrac{gr^2}{G}

(c) I'm not sure what the problem is asking for but here goes. As r doubles, F_G becomes

F_G = G\dfrac{m_1m_2}{(2r)^2} = \dfrac{1}{4}\left(G\dfrac{m_1m_2}{r^2}\right)

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Ymorist [56]
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Answer:

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