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Effectus [21]
3 years ago
5

Convert 0.001 to a power of ten

Mathematics
1 answer:
Elenna [48]3 years ago
8 0
0.001 = 10^{-3}
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oksian1 [2.3K]

Answer:

Step-by-step explanation:

7 0
2 years ago
PLEASE HELP What is the x value??
Mrrafil [7]

Answer:

9

Step-by-step explanation:

21^2-19^2=80

sqaure root of 80 to the nearest 10th is

6 0
2 years ago
A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimet
Dima020 [189]
Let's find the perimeter of the window.

The bottom side is x. The left and right sides make 2y.
The perimeter of a circle is 2\pi r, so the perimeter of a semicircle must be \pi r, The radius is \frac{1}2x, so that gives \frac{1}2\pi x for the curve. All of that is equal to 12.

x+2y+\frac{1}2\pi x=12

We only want to use one variable to create the area formula, so let's solve for y.

2y=12-x-\frac{1}2\pi x

y=6-\frac{1}2x-\frac{1}4\pi x

Now that we have a value for y in terms of x, we can find the area in terms of x.

The area of the rectangle is going to be xy, which then becomes

A_r=x(6-\frac{1}2x-\frac{1}4\pi x

A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2

The area of the semicircle is going to be \frac{1}2\pi r^2.

Since r=\frac{1}2x, A_{sc}=\frac{1}2\pi (\frac{1}2x)^2.

A_{sc}=\frac{1}2\pi \frac{1}4x^2

A_{sc}=\frac{1}8\pi x^2

Now let's add the areas of the rectangle and semicircle.

A=A_r+A_{sc}

A=6x-\frac{1}2x^2-\frac{1}4\pi x^2+\frac{1}8\pi x^2

A=6x-\frac{1}2x^2-\frac{1}8\pi x^2

If you wanted to factor out \frac{1}8 like you did, this would become

\boxed{A(x)=\frac{1}8(48x=4x^2-\pi x^2)}

Now what we want to do is find what x is when A is at its highest point, Once we have the value for x we can also find the value for y, of course.

Let's put our equation in the general form of a quadratic.

A(x)=(-\frac{1}2-\frac{1}8\pi )x^2+6x

Now we can use the vertex formula x=\frac{-b}{2a}.
(a and b refer to ax^2+bx+c.)

x=\frac{-6}{2(-\frac{1}2-\frac{1}8\pi)}

x=\frac{-6}{-\frac{1}4\pi -1}

x=\frac{-24}{-\pi -4}

\boxed{x=\frac{24}{\pi +4}}

Now let's plug that in for y=6-\frac{1}2x-\frac{1}4\pi x.

Since our final answers are in decimal form and not exact form, we can make our lives a little easier here and just use x\approx3.36059492.

y\approx6-\frac{1}2(3.36059492)-\frac{1}4\pi(3.36059492)

<span>y\approx6-(1.68029746+2.63940507809)

</span><span>\boxed{y\approx1.68029746191}

Let's take our answers for x and y and round to 2 decimal places.

\boxed{x\approx 3.36\ ft}

\boxed{y\approx 1.68\ ft}</span>
3 0
3 years ago
I dont get it i tried working on it and its hard
olga55 [171]
On the cube, it measures in numerical order 1 to 6, so:
1,2,3,4,5,6.
We are finding how much red fabric was used for even numbered sides.

So we are looking for sides 2,4,6

Since 20 in. is measured on a side, we can determine the area: 20*2= 40 in.^2 (all sides are same and length*width)

Now we have how much fabric is used on each side, so apply the area to all the even numbers (2,4,6)

40*3= 120 inches
3 0
3 years ago
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