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navik [9.2K]
4 years ago
3

What would the empirical formula be for the molecular compound c6h9o4?

Chemistry
1 answer:
Amiraneli [1.4K]4 years ago
3 0
Molecular compoun: C6H9O4

Each number to the right to the symbol of an atom is a subscript and represents the number of atoms of that element that is in the formula.

The empirical formula is the most reduced formula that shows the right ratio of all the atoms with whole numbers.

The you have to find is there is a set of numbers that have the same ratios: 6:9:4 but has lower whole numbers.

That is only possible if the three numbers ha a common divisor, which is not the case. This is, there is not a whole number that is a divisor of 6, 9 and 4, and that means that the empirical formula is the same formula shown C6H9O4.

Answer: the empirical formula is C6H9O4.
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Why are Li Na and k Placed in the same group of the periodic table?<br><br>​
Rudiy27

Answer:

Their valence electrons/properties

Explanation:

Elements in the same group of the periodic table have the same amount of valence electrons, which determines how they bond with other elements in other groups. This also determines their properties such as their reactivity. Since Li, Na, and K are in the same group, they must have similar properties and the same amount of electrons in their outermost shell.

5 0
4 years ago
Sabendo que os calores de combustão do enxofre monoclínico e do enxofre rômbico são, respectivamente, - 297,2 kJ/mol e - 296,8 k
liq [111]

Responda:

+ 0,9kJ / mol

Explicação:

Dados os calores de combustão do enxofre monoclínico e enxofre rômbico como - 297,2 kJ / mol e - 296,8 kJ / mol, respectivamente para a variação na transformação de 1 mol de enxofre rômbico em enxofre monoclínico conforme mostrado pela equação;

S (mon.) + O2 (g) -> SO2 (g)

Uma vez que são todos 1 mol cada, a mudança na entalpia será expressa como ∆H = ∆H2-∆H1

Dado ∆H2 = -296,8kJ / mol

∆H1 = -297,2kJ / mol

∆H = -296,8 - (- 297,2)

∆H = -296,8 + 297,2

∆H = 297,2-296,8

∆H = + 0,9kJ / mol

Portanto, a mudança na entalpia da equação é + 0,9kJ / mol

4 0
3 years ago
A plane flies from NY to LA at a constant speed of 800 km/hr. How long will it take the plane to fly the 4200 km? 5​
expeople1 [14]
5 hours and 25 minutes
5 0
3 years ago
What is the volume (in cubic inches) of 3.8 lb of titanium?
makkiz [27]

Given the mass of Titanium = 3.8 lb

Density of Titanium is 4.506 \frac{g}{cm^{3} }

We can calculate the volume of Titanium using density and mass.

Converting mass from lb to g:

3.8lb *\frac{453.6 g}{1 lb} = 1724 g

Calculating the volume of Titanium using density and mass:

1724 g * \frac{cm^{3} }{4.506g} =382.6 cm^{3}

Converting volume from cm^{3} to in^{3}:

382.6 cm^{3} * \frac{ 1 in^{3} }{16.39cm^{3} } = 23.34 in^{3}

7 0
4 years ago
What is the engine piston displacement in liters of an engine who’s displacement is listed as 430 in.²
sergeinik [125]

For an engine whose displacement is listed as 430 in.², the engine piston displacement in liters is mathematically given as

PD= 7.37 L  

<h3>What is the engine piston displacement in liters of an engine whose displacement is listed as 430 in.²?</h3>

Generally, the equation for the dimensional analysis method,\, we convert in to L is mathematically given as

l*(v/l)*l/v

Therefore,  piston displacement

PD=(450 in3) . (1 dm3 / 61.024 in3) . (1 L / 1 dm3)

PD= 7.37 L  

In conclusion, piston displacement

PD= 7.37 L  

Read more about volume

brainly.com/question/1578538

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6 0
3 years ago
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