All categories

3 years ago

What is the engine piston displacement in liters of an engine who’s displacement is listed as 430 in.²

1 answer:

6 0

For an engine whose displacement is listed as 430 in.², the engine piston displacement in liters is mathematically given as

PD= 7.37 L

<h3>What is the engine piston displacement in liters of an engine whose displacement is listed as 430 in.²?</h3>

Generally, the equation for the dimensional analysis method,\, we convert in to L is mathematically given as

l*(v/l)*l/v

Therefore, piston displacement

PD=(450 in3) . (1 dm3 / 61.024 in3) . (1 L / 1 dm3)

PD= 7.37 L

In conclusion, piston displacement

PD= 7.37 L

You might be interested in

Specific heat and thermal Energy question. Will give brailiest. 30 points please answer!! ASAP

USPshnik [31]

What’s the question?

3 0

3 years ago

Read 2 more answers

When a 0.235-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.275-g sample

andrew-mc [135]

Answer : The heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

Explanation :

First we have to calculate the specific heat calorimeter.

Formula used :

$Q=m\times c\times \Delta T$

where,

Q = heat of combustion of benzoic acid = 26.38 kJ/g = 26380 J/g

m = mass of benzoic acid = 0.235 g

c = specific heat of calorimeter = ?

$\Delta T$ = change in temperature = $1.643^oC$

Now put all the given value in the above formula, we get:

$26380J/g=0.235g\times c\times 1.643^oC$

$c=68323.38J/^oC$

Thus, the specific heat of calorimeter is $68323.38J/^oC$

Now we have to calculate the heat of combustion of caffeine.

Formula used :

$Q=c\times \Delta T$

where,

Q = heat of combustion of caffeine = ?

c = specific heat of calorimeter = $68323.38J/^oC$

$\Delta T$ = change in temperature = $1.584^oC$

Now put all the given value in the above formula, we get:

$Q=68323.38J/^oC\times 1.584^oC$

$Q=108224.23J=108.2kJ$

Now we have to calculate the moles of caffeine.

$\text{Moles of caffeine}=\frac{\text{Mass of caffeine}}{\text{Molar mass of caffeine}}$

Mass of caffeine = 0.275 g

Molar mass of caffeine = 194.19 g/mole

$\text{Moles of caffeine}=\frac{0.275g}{194.19g/mole}=0.00142mol$

Now we have to calculate the heat of combustion per mole of caffeine at constant volume.

$\text{Heat of combustion per mole of caffeine}=\frac{108.2kJ}{0.00142mol}=76197.18kJ/mole$

Therefore, the heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

4 0

3 years ago

I know the correct answer is either a or d. Can anyone explain which one it is and why? CH3C ≡ CCH2CH2Cl is named: a. 1-chloro-3

lara31 [8.8K]

Answer:

Explanation:

CH₃C≡ CCH₂CH₂Cl

Since there are 5 carbons so the suffix used is "pent"

There is a triple bond so its alkyne

So the compound becomes 2-pentyne (2 because the triple bond is with the 2nd carbon)

Then,

The functional group of chlorine is attached with 5th carbon So the compound becomes

5-chloro,2-pentyne

8 0

3 years ago

If E is the symbol for an element, which two of the following symbols represent isotopes of the same element?

UNO [17]

Answer: A and D

Explanation: isotopes must have same atomic number but different mass number due to the difference in their Neutron number

7 0

3 years ago

The mass of an object on the Moon would have _______________ mass if it was moved to Earth.

GREYUIT [131]

Answer:

I think its A. Because space has no gravity..

Explanation:

6 0

3 years ago