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lions [1.4K]
3 years ago
12

Please help! Which of the following number lines best represents all the solutions of the inequality? x < 4

Mathematics
2 answers:
Andru [333]3 years ago
7 0

Answer: B

Step-by-step explanation:

maksim [4K]3 years ago
7 0

Step-by-step explanation:

the answer is b

because x is less than 4 the arrow moves from 4 to the lower side of the line and the circle isn't shaded because x is less than four not less than or equal to

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Find the missing value for the exponential function represented by the table below.
Virty [35]
The common ratio of sequential values is 
   18.2/26 = 0.7

The missing value is
   12.74*0.7 = 8.918

The appropriate choice is ...
   d.  8.918
3 0
3 years ago
A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume
mixer [17]

Answer:

(a) 0.4096

(b) 0.64

(c) 0.7942

Step-by-step explanation:

The probability that the player wins is,

P(W)=0.80

Then the probability that the player losses is,

P(L)=1-P(W)=1-0.80=0.20

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = 1-P(L)-P(WL)

                                    =1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64

Thus, the probability that the player defeats at least two opponents in a game is 0.64.

(c)

Let <em>X</em> = number of times the player defeats all 4 opponents.

The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable X\sim Bin(n=3, p=0.4096)

The probability distribution of binomial is:

P(X=x)={n\choose x}p^{x} (1-p)^{n-x}

The probability that the player defeats all the 4 opponents at least once is,

P (<em>X</em> ≥ 1) = 1 - P (<em>X</em> < 1)

             = 1 - P (<em>X</em> = 0)

             =1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942

Thus, the probability that the player defeats all the 4 opponents at least once is 0.7942.

3 0
3 years ago
A seven digit number has 0 in the one's place a 6 in the ten thousand s place an 8 in the millions place and a fives in each of
vladimir2022 [97]
8,565,550
just replace 5 with the number
4 0
2 years ago
5.3.21<br>Solve the equation P= r+t+s for r<br>(Simplify your answer.)​
Sever21 [200]

Answer:

   r = P -t -s

Step-by-step explanation:

This is a one-step linear equation in r. Subtract the terms that don't contain r:

  P = r + t + s . . . . . . . . . .  given

The terms on the right that don't include r are (t+s). We want to subtract that to get r by itself.

  P -(t+s) = r +(t+s) -(t+s) . . . subtract (t+s)

  P -t -s = r . . . . . . . . . . . . . . simplify

  r = P - t - s

8 0
3 years ago
Anyone know this??<br> Pls help like now.
tankabanditka [31]
A'(-4, 3) i think is the answer
7 0
3 years ago
Read 2 more answers
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