For this case we have the following vector:
v = (- 8, 2)
Using product point we have:
v.v = (-8, 2). (- 8, 2)
v ^ 2 = (-8) * (- 8) + (2) * (2)
v ^ 2 = 64 + 4
v ^ 2 = 68
v = root (68)
v = root (4 * 17)
v = 2 * root (17)
Answer:
v = 2 * root (17)
option c
Answer:
True
Step-by-step explanation:
A six sigma level has a lower and upper specification limits between
and
. It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:
.
The probability of defects is:

Well, the defects present in a six sigma level and a five sigma level are, respectively:
Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>
[1]
[2]
Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.
Answer:
Not really an answer just warning you didn't actually attach a graph
Answer:
If the measures of the corresponding sides of two triangles are proportional then the triangles are similar. Likewise if the measures of two sides in one triangle are proportional to the corresponding sides in another triangle and the including angles are congruent then the triangles are similar