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xz_007 [3.2K]
2 years ago
11

What is the question 15%of258

Mathematics
1 answer:
Readme [11.4K]2 years ago
4 0
The answer would be 219.3 (:
Please mark me the brainliest ty
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The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
A crane lifts a 425 kg steel beam vertically a distance of 66 m. How much work does the crane do on the beam if the beam acceler
Fiesta28 [93]
<span>The solution to the problem is as follows:

W=Fd=mad=425*1.8*66 =50490 J

Therefore, it takes </span><span>50490 J of work the crane will do to accelerate the beam upward at 1.8 m/s^2.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
6 0
3 years ago
Read 2 more answers
Find the volume of the given prism. Round to the nearest tenth if necessary.
BigorU [14]

Answer: 616

Explanation:

When finding the volume of an object use: LxWxH

L=14

W=11

H=4

Now multiply 14x11x4=616


-LizzyIsTheQueen

4 0
3 years ago
The triangles below are similar; find the correct value of x. If necessary, round to the nearest tenths place.
Alekssandra [29.7K]
Where the triangle at?
4 0
2 years ago
Which is the solution to <br> 2<br> x<br> −<br> 6<br> +<br> 4<br> =<br> 14<br> ?
Kaylis [27]

Answer:

x=8

Step-by-step explanation:

2x-6+4=14

Combine like terms

2x-2=14

Add 2

2x=16

Divide

x=8

Checking work)

2(8)-2=14

16-2=14

14=14

8 0
2 years ago
Read 2 more answers
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