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xeze [42]
3 years ago
12

What characters are in Tekken 3

Computers and Technology
1 answer:
MrMuchimi3 years ago
6 0

Answer:Tekken 3 features a largely new cast of characters, including the debut of several now-staple characters such as Jin Kazama, Ling Xiaoyu, Bryan Fury, Eddy Gordo and Hwoarang, with a total of twenty-three characters.

Explanation: I feel like the answer is pretty strait forward.

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Why is the computer uses binary why not trinary?​
Ray Of Light [21]

Explanation:

because they only function with that one the gates also prevent it from being able to use it

3 0
2 years ago
A browser is an example of a. :
UNO [17]
A browser is an example of a system application
5 0
2 years ago
What is the output of the following code?
Lynna [10]

Answer:

The output is 24

Explanation:

Given

The above code segment

Required

The output

We have (on the first line):

x = 6

y = 3

z=24

result=0

On the second line:

result = 2*((z/(x-y))\%y+10)

Substitute the value of each variable

result = 2*((24/(6-3))\%3+10)

Solve the inner brackets

result = 2*((24/3)\%3+10)

result = 2*(8\%3+10)

8%3 implies that, the remainder when 8 is divided by 3.

The remainder is 2

So:

result = 2*(2+10)

result = 2*12

result = 24

<em>Hence, the output is 24</em>

8 0
2 years ago
URGENT!
lutik1710 [3]

<u>Explanation:</u>

Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:

// C++ program to count  even digits  in a given number .

#include <iostream>  

using namespace std;  

// Function to count digits

int countEven(int n)  

{  

int even_count = 0;    

while (n > 0)  

{  

 int rem = n % 10;  

 if (rem % 2 == 0)  

  even_count++;  

 n = n / 10;  

}  

cout << "Even count : "

 << even_count;  

if (even_count % 2 == 0 )  

 return 1;  

else

 return 0;  

}  

// Driver Code  

int main()  

{  

int n;  

std::cin >>n;

int t = countEven(n);  

return 0;  

}  

6 0
2 years ago
Use the variables k and total to write a while loop that computes the sum of the squares of the first 50 counting numbers, and a
pshichka [43]
Int   k=0.total=0;
while(k++<50)
    total+=k*k;
    

5 0
3 years ago
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