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zhuklara [117]
4 years ago
13

TIFF is the default file format for most digital cameras. State True or False.

Computers and Technology
1 answer:
Gala2k [10]4 years ago
3 0
That statement is false

Without any editing, the default file format for most digital cameras that currently exist in the market is JPG

hope this helps
You might be interested in
Given main() and a base Book class, define a derived class called Encyclopedia. Within the derived Encyclopedia class, define a
NemiM [27]

Answer:    

Here is the Encyclopedia class:

public class Encyclopedia extends Book {   //class  Encyclopedia that inherits from class Book

  private String edition; //declare private member variable edition of type String  

  private int numVolumes;      //declare private member variable numVolumes of type int

  public void setEdition(String ed) {  //mutator method of class that sets the value of edition

     edition = ed;    }     //assigns the value of ed to edition member field

  public void setNumVolumes(int numVol) { //mutator method of class that sets the value of numVol

     numVolumes = numVol;    }  //assigns the value of numVolumes to edition member field

  public String getEdition() {  //accessor method to get the value of edition

     return edition;    }     //returns the current value of edition

  public int getNumVolumes() {  //accessor method to get the value of numVolumes

     return numVolumes;    }       //returns the current value of numVolumes

  public void printInfo() {  //method to print edition and number of volumes information on output screen

     super.printInfo();  // The super keyword refers to parent class Book objects. It is used to call Book method and to eliminate the confusion between Book class printInfo method and Encyclopedia printInfo  method

     System.out.println("   Edition: " + edition);  //prints edition info

     System.out.println("   Number of Volumes: " + numVolumes);    }  }  //prints number of volumes info

Explanation:

The explanation is provided in the attached document.

7 0
4 years ago
Can somebody tell me the Minecraft command to clear an entire world and destroy every block if u Dunno please don’t answer >-
aalyn [17]

Answer:

You can't, but..

Explanation:

You cannot "clear" an already existing world.

But you can create a new one, click on "More world options", then click on "world type" until it says "superflat", and then you can click on customize and there you can remove every layer, therefore making the world to not spawn with blocks.

7 0
3 years ago
The Bellman-Ford algorithm for the shortest path problem with negative edge weights will report that there exists a negative cyc
Feliz [49]

Answer:

- Iterate over the Bellman-Ford algorithm n-1 time while tracking the parent vertex and store in an array.

- Do another iteration and if no relaxation of the edges occurs in the nth iteration then print of return "There are no negative cycle".

- Else, store the vertex of the relaxed edge at the nth iteration with a variable name.

- Then iterate over the vertexes starting from the store vertex until a cycle is found then print it out as the cycle of negative weight.

Explanation:

The Bellman-Ford algorithm can be used to detect a negative cycle in a graph. The program should iterate over the algorithm, in search of a relaxed edge. If any, the vertex of the specified edge is used as a starting point to get the target negative cycle.

3 0
3 years ago
Consider the following arrays. 1 4 21 2 4 100 B # 111(A) L3π 42 Write MATLAB expressions to do the tollowing a. Select just the
andriy [413]

Answer:

Complete Matalb code along with explanation and output results are given below

Explanation:

We are given following two matrices A and B of size 4x3

A = [1 4 2; 2 4 100; 7 9 7; 3 pi 42]

B = log(A)

(a) Select just the second row of B

% to extract any row use this syntax  B(row no, : )  we can also extract more than 1 row or any particular elements in a specific row

B_row_2 = B(2,:)

(b) Evaluate the sum of the second row of B

% simply use the sum function and pass it any vector or matrix and it will return their sum

sum_B_row_2 = sum( B_row_2(:) )  

(c) Multiply the second column of B and the first column of A element by element

% first we extract the column 2 of matrix B and column 1 of matrix A. use this syntax  B( : ,col no ) to extract any column  

B_col_2 = B(:,2)

A_col_1 = A(:,1)

% Then we use ( .*) to multiply element by element. To use standard multiplication of matrices only use asterisk sign without coma

multiply=B_col_2.*A_col_1

(d) Evaluate the maximum value in the vector resulting from element-by- element multiplication of the second column of B with the first column of A

% we can find the maximum value in a vector or matrix by using max function so we pass the multiply variable where our result was stored

max_value = max(multiply)

(e) Use element-by-element division to divide the first row of A by the first three elements of the third column of B. Evaluate the sum of the elements of the resulting vector

%  First we extract the row 1 of matrix A

A_row_1 = A(1,:)

%  Then we extract the column 3 of matrix B

B_col_3 = B(:,3)

%  Then we extract the first 3 elements of column 3 of matrix B

B_col_3 = B_col_3(1:3)

% Finally we use ( ./ ) to use element by element division

divide = A_row_1./B_col_3

% Using the sum function again results in the addition of entire elements of resultant matrix

sum_divide = sum( divide(:) )

Only Code:

A = [1 4 2; 2 4 100; 7 9 7; 3 pi 42]

B = log(A)

B_row_2 = B(2,:)

sum_B_row_2 = sum( B_row_2(:) )  

B_col_2 = B(:,2)

A_col_1 = A(:,1)

multiply=B_col_2.*A_col_1

max_value = max(multiply)

A_row_1 = A(1,:)

B_col_3 = B(:,3)

B_col_3 = B_col_3(1:3)

divide = A_row_1./B_col_3

sum_divide = sum( divide(:) )

Output Results:

A =

    1.0000     4.0000     2.0000

    2.0000     4.0000   100.0000

    7.0000     9.0000     7.0000

    3.0000     3.1416    42.0000

B =  

  0.00000   1.38629   0.69315

  0.69315   1.38629   4.60517

  1.94591   2.19722   1.94591

  1.09861   1.14473   3.73767

B_row_2 =   0.69315   1.38629   4.60517

sum_B_row_2 =  6.6846

B_col_2 =  

  1.3863

  1.3863

  2.1972

  1.1447

A_col_1 =

  1

  2

  7

  3

multiply =

   1.3863

   2.7726

  15.3806

   3.4342

max_value =  15.381

A_row_1 =     1   4   2

B_col_3 =  

  0.69315

  4.60517

  1.94591

  3.73767

B_col_3 =

  0.69315

  4.60517

  1.94591

divide =

  1.44270   5.77078   2.88539

  0.21715   0.86859   0.43429

  0.51390   2.05559   1.02780

sum_divide =  15.216

6 0
3 years ago
Which of the following statements are valid in Java? (Assume that console is Scanner object initialized to the standard input de
san4es73 [151]

Answer:

Both (i) and (ii) are valid in Java

Explanation:

In (i) 'area' is a variable property of the object myCircle. It could be assigned a value. In this case it has been assigned a value equal to the product of 3.14 and the square of the read input of type double from the keyboard.

After assigning a value to area, it could be printed directly to the console using the println method.

In (ii) 'area' is a method property of the object myCircle. It could be called when the value of the radius(r) has been set using a second method 'set' of myCircle. The call to myCircle.area() probably prints the area of the circle, myCircle, to the console.

In summary, though different, both are valid ways of doing the same thing.

Hope this helps!

6 0
3 years ago
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