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3 years ago

3175÷66 partial quotient

Mathematics

1 answer:

Serga [27]3 years ago

3 0

20.83333333333333333

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4. Normal body temperature is 98.6 degrees Fahrenheit, although it varies slightly for some people.

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2 years ago

HELP ASAPJennifer and Chris completed some chores and split the earnings in the ratio 3:2. Jennifer earned $48.

elixir [45]

Let the total earnings be = x

Jennifer and Chris split the earnings in the ratio 3:2

Jennifer earned = $48

$\frac{3x}{5}=48$

$3x=240$

x=80

Hence total earnings are $80

(a) Chris earning is = $\frac{2x}{5}=\frac{2*80}{5}=32$

Hence, Chris earns $32

(b) Jennifer spends 30% of her earnings on a book.

So, price of the book = $\frac{30}{100}\times48$

Price of book = $14.40

(c) Jennifer also buys a magazine for = $5.40

So, total money Jennifer spent on book and magazine = 14.40+5.40=19.80

Money left with Jennifer = 48-19.80= $28.20

In fractions = $\frac{28.20}{48}$

or multiplying the numerator and denominator by 10, we get

$\frac{282}{480}$ = $\frac{47}{80}$

(d) Let the original price of the shirt = x

reduction percentage on x= 40%

Price paid after reduction = 16.80

$\frac{40x}{100}=16.80$

$40x=1680$

$x=42$

Hence, the original price of the shirt was $42.

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3 years ago

For every 4 hours Michelle works, she gets a 15 minute break. Which equation shows the proportional relationship between the num

Lady_Fox [76]

Answer:

b=8w

Step-by-step explanation:

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2 years ago

Read 2 more answers

-Dominant- [34]

Answer:

All four

Step-by-step explanation:

SSS, SAS, ASA, and HL

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2 years ago

In 1990, the population of Boston, Massachusetts was 574,283. In 2000, the population was 589,141. What is the percent of change

MrMuchimi

Answer:

Percent of change in population is $2.6$ %

Step-by-step explanation:

Given population of Boston is $574,283$ measured in year $1990$ .

And population of Boston in year $2000$ is $589,141$ .

We need to find percent of change in population.

So, percent change $=\frac{New\ population-Old\ population}{Old\ population}\times100$ %

Here old population is $574,283$ and new population is $589,141$

Plugging these value in formula we get,

Percent change $=\frac{589,141-574,283}{574,283}\times100\\\\=\frac{14858}{574,283}\times100=0.0258\times100\\\\=2.587$

Rounding to nearest tenth 2.6%

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3 years ago