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3 years ago

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3175÷66 partial quotient

1 answer:

Serga [27]3 years ago

3 0

20.83333333333333333

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Cos x = sin 34°<br> What is the value of x?<br> Enter your answer in the box.

vredina [299]

$\bf \textit{Cofunction Identities} \\\\ sin\left(90^o-\theta\right)=cos(\theta) \qquad cos\left(90^o-\theta\right)=sin(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ cos(x)=\stackrel{90-56}{sin(\stackrel{\downarrow }{34^o})}\implies cos(\stackrel{\downarrow }{x})=sin(90^o-\stackrel{\downarrow }{56^o})\implies cos(56^o)$

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3 years ago

Read 2 more answers

Which of the following rational functions is graphed below?

Lady_Fox [76]

Answer:

B. $f\left(x\right)=\frac{x}{\left(x+4\right)\left(x-1\right)}$

Step-by-step explanation:

I graphed this function on the graph below and it matched the graph you have.

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3 years ago

the number of subscriptions to an interior design magazine was 16,450 in 1996. Since then, the number of subscriptions has incre

babunello [35]

Answer:

49,744.8 so round up to 49,745

Step-by-step explanation:

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3 years ago

9) State the coordinates of the endpoints of a<br> line segment that intersects the y-axis.

eduard

Answer:

(5,4) and (3,4)

Step-by-step explanation:

A line segment has 2 end points which can be denoted as:

$(x_1,y_1)$ and $(x_2,y_2)$

When this line segment intersects at y.

This means that the coordinate on the y axis is the same at both end points

i.e.

$y_1 = y_2 = y$

$(x_1,y_1)$ and $(x_2,y_2)$ becomes $(x_1,y)$ and $(x_2,y)$

x1 and x2 can be any value but the y value must remain unchanged

Using the above analysis, a possible coordinate is:

$(5,4)$ and $(3,4)$

Note that there are as many answers as possible as long as the coordinate pair satisfy is of the form $(x_1,y)$ <em> and </em> $(x_2,y)$ <em />

Take for instance, another possible pair is:

$(1,-3)$ and $(0,-3)$

7 0

3 years ago

Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts

shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

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3 years ago