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dangina [55]
3 years ago
6

Find the percent of the number. What is 256% of 75

Mathematics
2 answers:
astra-53 [7]3 years ago
6 0
192 is the percent of 256 of 75
Nostrana [21]3 years ago
4 0

It is 192.

75 is 100%  so we can write it down as 75=100%.

75=100%  x=256%

CROSS MULTIPLY, proportions.

75/100     X/256

19200/100 equals 192

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Drag each tile to the correct box.
Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

f(a)=h(3)=4  

f(b)=h(5)=16

a=3

b=5

Substitute

\frac{16-4}{5-3}=6

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

f(a)=f(3)=10  

f(b)=f(6)=35

a=3

b=6

Substitute

\frac{35-10}{6-3}=8.33

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

g(x)=\frac{1}{5}(4)^x

f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}  

f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}

a=2

b=3

Substitute

\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0
3 years ago
Which of the following steps can be performed so that the square root property may easily be applied to 2x2 = 16? (1 point)
Ivan

Answer:

\Large \boxed{\mathrm{Option \ 2}}

Step-by-step explanation:

2x^2 =16

The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is x, so divide both sides by 2 before applying the square root property.

The x variable should be isolated on one side of the equation. The x variable is squared so before performing the square root property where we take the square root of both sides, we divide both sides by 2, then take the square root of both sides.

Dividing both sides by 2.

\displaystyle \frac{2x^2 }{2} =\frac{16}{2}

x^2 =8

Taking the square root of both sides.

\sqrt{x^2 } =\pm \sqrt{8}

x=\pm 2\sqrt{2}

7 0
3 years ago
Read 2 more answers
This equation x (x2 - 1) y"+ (1- x?) y' +9(2x - 2)y has a regular singular points at x =​
KiRa [710]

Answer: the nots confused me y’ is that integral or what

Step-by-step explanation:

4 0
3 years ago
Brainliest to the correct answer. Only rule is you can't search it up.
Genrish500 [490]
I think a candle lol
5 0
2 years ago
What is 1.25 rounded to the nearest tenths
MAXImum [283]
It would be 1.30 or 1.3
3 0
3 years ago
Read 2 more answers
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