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guapka [62]
4 years ago
7

has developed a new battery for its portable navigation systems. To help market this system, the company wants to know how long,

on average, the batteries last before they burn out. The company tests a random sample of 100 batteries and find that the sample mean is 80 hours, with a sample standard deviation of 20 hour What is the point estimate for the mean lifetime of the batteries
Mathematics
1 answer:
MrRa [10]4 years ago
5 0

Answer:

<em>The sample mean (x⁻) = 80 hours is a point estimate for  the mean lifetime of the batteries</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<u><em>Point  Estimate:-</em></u>

The sample mean (x⁻) is a point estimate of the Population mean 'μ'

Given data

mean of the sample (x⁻) = 80 hours

<em>Therefore The sample mean (x⁻) = 80 hours is a point estimate for  the mean lifetime of the batteries.</em>

<em>and </em>

The sample standard deviation (s) is a point estimate of the Population standard deviation(σ).

Given data

standard deviation of the sample (s) = 20 hours

<em>Therefore The sample standard deviation (s) = 20 hours is a point estimate of the Population standard deviation(σ).</em>

<em></em>

<em></em>

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Which expression represents the distance between the points (11, 4) and (5,8)?
antiseptic1488 [7]

Answer:

\displaystyle d = 2\sqrt{13}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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Point (5, 8) → x₂ = 5, y₂ = 8

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                       \displaystyle d = \sqrt{(5-11)^2+(8-4)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                 \displaystyle d = \sqrt{(-6)^2+(4)^2}
  3. [√Radical] Evaluate exponents:                                                                    \displaystyle d = \sqrt{36+16}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{52}
  5. [√Radical] Simplify:                                                                                         \displaystyle d = 2\sqrt{13}
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Substitute the value of the variable into the expression and simplify.

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Step-by-step explanation:

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