I don’t think it’s any of them i went through and tried all of them and none of them were equal. I honestly could just suck
Answer:
The roots are real and distinct.
Step-by-step explanation:
Given the following equation:

In this problem, a = 1, b = k and c = -k - 2
The discriminant is b² - 4ac, and for the roots to be real and distinct, it must be at least or greater than 0.
We get,
(k)²- 4(1)(-k - 2) = 1 - 4(-k - 2)
= k² + 4k + 8
Let's check:
At k = -2,

At k = 0,

At k = -100,

Therefore, we can conclude that for all values of k, the roots are real and distinct.
This has been a long way in answering this question, so it would be great if you could mark me as brainliest
Answer:
a = 1√6
b = -2
Step-by-step explanation:
Hello,
To solve this trigonometric problem, we need to convert this values into fractions
a).
Sin45° = 1/√2
cos30° = √3/2
Sin60° = √3/2
Sin45° / (cos30° + sin60°) = [(1/√2) ÷ (√3/2 + √3/2)]
(1/√2) ÷ (√3/2 + √3/2)
Add √3/2 + √3/2
1/√2 ÷ 2√3/2
1/√2 × 2/2√3
2/2√(2×3)
2/2√6
1/√6
b
Cos 180° = -1
Sin150° = ½
Tan135° = -1
2cos180° - 2sin150° - tan135°
(2 × -1) - (2×½) - (-1)
-2 - 1 + 1 = -2
Answeri don't get the equestion your trying to say
Step-by-step explanation:
Answer:
Step-by-step explanation:
Yes; the 3 points all lie on EG.