Answer:
B. y = tan x and C. y = cot x
Step-by-step explanation:
Range:
range is defined as the set of values that any given function y=f(x), can take for which the x values are defined. It is the value that y can take for the values of x.
Given:
From the given options
the range of tanx and cotx are all real numbers
as the period of tanx and cotx are π
where as range of secx is all real numbers except π/2 + n*π i.e.
(-∞ , -1] U [1 , + ∞)
And range of cscx is all real numbers except n*π i.e.
(-∞ , -1] U [1 , + ∞)
So from the given option:
option B and C are correct while A and D are not !
106=x+x+5+x+8
106=3x+13
3x=93
x=31
(the sides are 31, 36, 39 respectively)
Answer:
a) 
And replacing we got:
b) 
And then the expected value would be:
Step-by-step explanation:
We assume the following distribution given:
Y 0 1 2 3
P(Y) 0.60 0.25 0.10 0.05
Part a
We can find the expected value with this formula:
And replacing we got:
Part b
If we want to find the expected value of 
we need to find the expected value of Y^2 and we have:
And replacing we got:
And then the expected value would be:
-20 because after the the thermometer hits zero the more negative the temperature gets the colder it is
<span>Let time taken by Luke to cover the distance = x hours
Speed of Luke = 6 miles per hour
Therefore, Distance covered by Luke = 6x ------(1)
Speed of Micah = 4 miles per hour
Since Micah walked 2 miles before Luke started running, Luke started 1/2 an hour after Micah started.
Therefore time taken by Micah to cover the distance = x+1/2
Distance covered by Micah = 4(x + 1/2) -------(2)
Equating (1) and (2)
6x = 4(x+1/2)
6x = 4x +2
2x = 2
x= 1
Therefore Luke would take 1 hour to cover the distance covered by Micah.</span>
