1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erica [24]
3 years ago
13

a certin shade of green paint is made from 5 parts yellow mixed with three parts blue. if 2 cans of yellow are used, how many ca

ns of blue should be used?
Mathematics
1 answer:
andrew-mc [135]3 years ago
4 0
__Brainliest if helped!

5 Parts Yellow with 3 Parts blue
5Yellow with 3 Blue
1Yellow would be  with 3/5 Blue
Hence , 
2 Yellow = (3/5)*2 Blue =6/5 Cans of blue  or 1.2Cans of blue. 
You might be interested in
What is the standard deviation of this data set? Use a calculator to help you.
ale4655 [162]

Answer:

Standard deviation = 14.064

Step-by-step explanation:

We are given the following data;

        X                          X - Xbar                  (X-Xbar)^{2}

       20                     20 - 46 = -26                    676

       23                     23 - 46 = - 23                    529

       32                     32 - 46 = -14                      196

       36                     36 - 46 = -10                      100

       41                      41 - 46 = -5                         25

       43                     43 - 46 = -3                          9

       44                     44 - 46 = -2                          4

       45                     45 - 46 = -1                           1

       47                      47 - 46 = 1                            1

       54                      54 - 46 = 8                        64

       55                      55 - 46 = 9                        81

      59                       59 - 46 = 13                      169

       61                       61 - 46 = 15                       225

       63                       63 - 46 = 17                      289

       66                       66 - 46 = 20                <u>     400    </u>    

                                                    \sum(X-Xbar)^{2} <u>= 2769 </u>

Firstly we will calculate Mean, Xbar = \frac{\sum X}{n}

  Xbar = \frac{20+ 23+ 32+ 36+ 41+ 43+ 44+ 45+ 47+ 54+ 55+ 59+ 61+ 63+ 66}{15} = 45.93 ≈ 46

Now, Standard deviation formula is given by;

                   s = \sqrt{\frac{ \sum(X-Xbar)^{2}}{n-1}} = \sqrt{\frac{ 2769}{15-1}} = 14.064 .

7 0
3 years ago
How do I do this? Please help me
AnnyKZ [126]
You divide 46 by 5.2 and the answer should be 8.8 inches.
7 0
3 years ago
X^2-6x=6<br> solve by completing the square
Ivanshal [37]
Hi!

The answer is x=3± \sqrt{15}
7 0
3 years ago
1/3(3x-6)=2x please help
german

Answer:

-2

Step-by-step explanation:

In the picture

4 0
2 years ago
Read 2 more answers
The answer is 288, but i don’t know how to get the answer. please give me an explanation.
andriy [413]
Sorry I don’t know the answer and also sorry about that other comment they are very rude I hope you find someone who actually knows the answer!! ❤️
3 0
2 years ago
Other questions:
  • (06.01)A spinner is divided into sections of equal size, of which some are red, some are blue, and the remaining are green. The
    11·2 answers
  • What is the maximum number of intersection points between a quadrilateral and a triangle?
    11·2 answers
  • How can you distinguish the base of an isosceles triangle from a leg?
    6·2 answers
  • For which of the following values of x does f(x) = -16?<br> -16<br> 12<br> 0<br> 8
    12·1 answer
  • What is 4- 1 1/4 + 1/2
    11·1 answer
  • Please Help Me I Rally Need The Awnser
    13·1 answer
  • Pls if anyone can solve NOW
    13·1 answer
  • How do the number of faces, vertices, and edges of a cube compare to the number of faces, vertices, and edges of a tetrahedron?
    14·1 answer
  • Can someone pls help with this tyyy
    9·1 answer
  • Combine Like terms
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!