All categories

3 years ago

Convert weeks to days>

Mathematics

1 answer:

madam [21]3 years ago

4 0

What is the question that you're asking?

You might be interested in

If the boy is 5’6 tall and his shadow is 4 ft and the shadow of the pole 18 ft determine the height of the pole to the nearest 1

Dominik [7]

The answer is 24.7ft

7 0

3 years ago

A researcher at a major clinic wishes to estimate the proportion of the adult population of the United States that has sleep dep

Thepotemich [5.8K]

Answer: n = 600.25 ≈ 601 ( sample size)

the minimum sample size of the adults in United State who have sleep deprivation is 601

Step-by-step explanation:

Given that;

the confidence level = 95% = 0.05

the Margin of error E = 4% = 0.04

∴ level of significance ∝ = 1 - C.L

∝ = 1 - (95/100)

= 0.05

Z∝/2 = 0.05/2 = 0.025

Z-critical value at 95% confidence level is OR level of significance at 0.025 = 1.96 (z-table)

Now to calculate the sample size, we say

n = (Z(critical) / M.E )² P ( 1 - P)

now we substitute

n = (1.96 / 0.04)² × 0.5 ( 1 - 0.5)

n = 2401 × 0.5 × 0.5

n = 600.25 ≈ 601

Therefore the minimum sample size of the adults in United State who have sleep deprivation is 601

6 0

3 years ago

30% of 60 is <br><br> 30%of ____ is 60

ololo11 [35]

You know that 3 times 2 is 6 so 30'times 20 equals 60

6 0

3 years ago

Read 2 more answers

What is the output value for the following function if the input value is 1?

Vera_Pavlovna [14]

Answer:

Explanation:

7 0

3 years ago

In 2008, data from the Center for Disease Control revealed that 28.5% of all male teenagers, aged 18-19 and attending U.S. colle

m_a_m_a [10]

Answer:

a) H0 : u = 28.5%

H1 : u < 28.5%

b) critical value = - 1.645

c) test statistic Z= - 1.41

d) Fail to reject H0

e) There is not enough evidence to support the professor's claim.

Step-by-step explanation:

Given:

P = 28.5% ≈ 0.285

X = 210

n = 800

$p' = \frac{X}{n} = \frac{210}{800} = 0.2625$

Level of significance = 0.05

a) The null and alternative hypotheses are:

H0 : u = 28.5%

H1 : u < 28.5%

b) Given a 0.05 significance level.

This is a left tailed test.

The critical value =

$-Z_0.05 = -1.645$

The critical value = -1.645

c) Calculating the test statistic, we have:

$Z = \frac{p' - P}{\sqrt{\frac{P(1-P)}{n}}}$

$Z = \frac{0.2625 - 0.285}{\sqrt{\frac{28.5(1-28.5)}{800}}}$

Z = -1.41

d) Decision:

We fail to reject null hypothesis H0, since Z = -1.41 is not in the rejection region, <1.645

e) There is not enough evidence to support the professor's claim that the proportion of obese male teenagers decreased.

5 0

3 years ago