Answer:
P = 33z + 3
Step-by-step explanation:
To find the perimeter (P) sum the 4 sides
P = 8z - 3 + 10z - 3 + 6z - 1 + 9z + 10 ← collect like terms
= (8z + 10z + 6z + 9z ) + (- 3 - 3 - 1 + 10)
= 33z + 3
We can't see any given circle. The general form for a circle centered at the origin with radius r is
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
