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elixir [45]
3 years ago
12

Please help and show work

Mathematics
1 answer:
Fantom [35]3 years ago
7 0
450.000/40 is 11.25
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Your part time job pays you $14/h. You work approximately 12 hours/week.
kirill115 [55]

Answer:

  1. <u>BOX 1 </u>=  672.00

(14 * 12 = 168

168 * 4 = $ 672 )

     2. <u>BOX 2</u> = 282.95

(Cell phone= $45 A MONTH

Eating outside = $50 A MONTH

12 .50 * 4   = 50   (4 WEEKS A MONTH )

Transportation =  131.2 A MONTH

32.80 * 4 = 131.2  (4 WEEKS A MONTH )

Movie =  $16.75 A MONTH

Charity = $ 40 A MONTH

10 * 4  (4 WEEKS A MONTH )

<u> MONTHLY EXPENSE </u> = 45 + 50 + 131.2 + 16.75 + 40

<u> MONTHLY EXPENSE </u> = 282.95 )

      3. <u>BOX 3</u> = 389.05

Money that can be saved = Monthly income - Monthly expense

Money that can be saved = 672 -  282.95

                                          = 389.05

<h2><em><u>please give brainliest </u></em></h2>
4 0
3 years ago
What is equivalent to 2r+(t+r)?<br><br> a. (t+r)<br> b. 2rt+4r<br> c. none of the above
abruzzese [7]
None of the above because (t+r) is just getting rid of the numbers which you can't do and I don't know where 4 even came from in b!
4 0
3 years ago
Read 2 more answers
Sami ordered 132 dresses for her store. what Is 132 rounded to the nearest ten
Pani-rosa [81]
132 is rounded to the 130 cause you just look at the last number and you see what is the closes zero that's why it is 130
4 0
4 years ago
Today only, a sofa is being sold at a 34% discount. The sale price is $297. What was the price yesterday?
spayn [35]

Answer:

$297? i think because if the sale is today only then maybe it's $297

3 0
4 years ago
If x^3 + 1/x^3 = 110 then find x + 1/x
Svetlanka [38]
Use:(a+b)^3=a^3+3a^2b+3ab^2+b^3\ (*)\\\\x^3+\left(\dfrac{1}{x}\right)^3\\=\underbrace{x^3+3\cdot x^2\cdot\dfrac{1}{x}+3\cdot x\cdot\left(\dfrac{1}{x}\right)^2+\left(\dfrac{1}{x}\right)^3}_{(*)}-3\cdot x^2\cdot\dfrac{1}{x}-3\cdot x\cdot\left(\dfrac{1}{x}\right)^2\\\\=\left(x+\dfrac{1}{x}\right)^3-3x-3\cdot\dfrac{1}{x}=\left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)

therefore

x^3+\left(\dfrac{1}{x}\right)^3=110\iff \left(x+\dfrac{1}{x}\right)^3-3\left(x+\dfrac{1}{x}\right)=110\\\\subtitute\ t=x+\dfrac{1}{x}\\\\t^3-3t=110\ \ \ \ |subtract\ 110\ from\ both\ sides\\\\t^3-3t-110=0\\\\t^3-25t+22t-110=0\\\\t(t^2-25)+22(t-5)=0\ \ \ |use\ a^2-b^2=(a-b)(a+b)\\\\t(t-5)(t+5)+22(t-5)=0\\\\(t-5)[t(t+5)+22]=0\iff t-5=0\ or\ \underbrace{t^2+5t+22=0}_{no\ solution}\\\\t=5\iff x+\dfrac{1}{x}=5\\\\Answer:\boxed{x+\dfrac{1}{x}=5}
3 0
4 years ago
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