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Julli [10]
4 years ago
5

A magnesium surface has a work function of 2.65 eV. Electromagnetic waves with a wavelength of 280 nm strike the surface and eje

ct electrons. Find the maximum kinetic energy of the ejected electrons. Express your answer in electron volts.
Physics
1 answer:
Neko [114]4 years ago
8 0

Answer:

Explanation:

Energy of radiation in eV = 1237.5/280 = 4.42 eV.

Work function = 2.65 eV.

Maximum kinetic energy = 4.42 - 2.65 = 1.77 eV.

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3 years ago
elements are organized based on their properties on a chart called modern periodic table which of the following statements is tr
Illusion [34]

Answer:

Elements are arranged in the table by increasing atomic number.

Explanation:

In the modern periodic table, each element is represented by its chemical symbol. The number above each symbol is its atomic number.

8 0
4 years ago
How many pennies does it cost to use your 956-W microwave for 36 minutes every day for a week if your electric company charges 9
Shtirlitz [24]
0.956kW X 0.6 hours
= 0.5736 kWh a day

0.5736kWh X 7
= 4.0152 kWh a week

4.0152 X $0.09
=$ 0.36
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6 0
3 years ago
Compare and contrast an earthquake and a tsunami.
Scorpion4ik [409]

Answer:

An earthquake is a trembling movement of the earth's crust. These tremors are generally caused by shifts of the plates that make up the earth's surface. ... A tsunami (pronounced soo-NAHM-ee) is a series of huge waves that occur as the result of a violent underwater disturbance, such as an earthquake or volcanic eruption.

Explanation:

4 0
3 years ago
Light with a wavelength of 600 nm shines onto a single slit, and the diffraction pattern is observed on a screen 2.5 m away from
Nostrana [21]

Answer:

"6.67 mm" is the right solution.

Explanation:

The given values are:

  • L = 2.5 m
  • y = .0125
  • λ = 600 nm

As we know, the equation

⇒  \frac{y}{L} =\frac{x \lambda}{a}

On substituting the values, we get

⇒  \frac{.0125}{2.5}=\frac{(1)(600\times 10^{-9}) }{a}

On applying cross multiplication, we get

⇒  .0125a=2.5 (600\times 10^{-9})

⇒          a=\frac{2.5(600\times 10^{-9})}{.0125}

⇒             =1.2\times 10^{-4} \ m

For new distance, we have to put this value of "a" in the above equation,

⇒  \frac{y}{1.5} =\frac{(1)(600\times 10^{-9})}{1.2\times 10^{-4}}

⇒  (1.2\times 10^{-4})y=1.5(600\times 10^{-9})

⇒                     y=\frac{1.5(600\times 10^{-9})}{1.2\times 10^{-4}}

⇒                        =3.22\times 10^{-3} \ m

The total distance will be twice the value of "y", we get

=  6.67\times 10^{-3} \ m

or,

=  6.67 \ mm

6 0
3 years ago
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