Given: Initial velocity of toy car (u ) = 0
Final velocity of toy car (v) = 0.12 m/s
Required time (t) = 0.1 s
To find: The acceleration of the toy car.
Let the acceleration of the toy car be (a)
Formula Used: 1st kinematic equation of motion
v = u + at ---------------------------(i)
Here, all alphabets are in their usual meanings
Now, from equation (i), we shall calculate the value of 'a'.
so, a = (v - u) /t
or, a = (0.12 m/s - 0) / 0.1s
or, a = 1.2 m/s²
Hence, the required acceleration of the toy car will be 1.2 m/s².
Answer:
2682
Explanation:
Work done is given by :
Work = Force x distance
= mg x d
So, work done in lifting the box of 23 kg up to my waist of 1 m high is :
W = mg x d
= 23 x 9.18 x 1
= 211.14
Now work done carrying the box horizontally 6 meters across the room is
W = mg x d
= 23 x 9.18 x 6
= 1266.84
Work done in placing the box on the shelf that is 5.7 m above the ground is
W = mg x d
= 23 x 9.18 x 5.7
= 1203.49
So the total work done is = 211.14 + 1266.84 + 1203.49
= 2681.47
= 2682 (rounding off)
Answer:
The maximum kinetic energy is 100 j.
Explanation:
<h3>The kinetic energy = (potential energy) + (kinetic energy) and the potential energy of 0 J implying its kinetic energy is 100 J, which is its maximum.
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Answer:
A
Explanation:
Iron and gadlinium are both very easily made into magnetic substances. Cobalt is also capable of being magnetized. Aluminum, put in an alloy, can make a magnetic substance, but
Aluminum by itself is not able to be magnetized.
To provide a greater certainty that the observed results are not by chance.