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Alex787 [66]
3 years ago
7

How strong is the attractive force between a glass rod with a 0.700μC0.700μC charge and a silk cloth with a –0.600μC–0.600μC cha

rge, which are 12.0 cm apart, using the approximation that they act like point charges?
Physics
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

0.2625 N/C

Explanation:

Force of attraction = \frac{K\timesQ_1\times Q_2}{R^2}

where Q₁ and Q₂ are charges and R is distance between charges.K is a constant equal to 9 x 10⁹.

= \frac{9\times10^9\times.7\times10^{-6}\times.6\times10^{-6}}{(12\times10^{-2})^2}

= 0.2625 N/C

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The sun's core _____. A) is made of solid helium B) makes up most of the sun's size C) creates energy by fusing hydrogen into he
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I think the correct answer is C
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3 years ago
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A train has an acceleration of magnitude 0.90 m/s2 while stopping. A pendulum with a 0.55-kg bob is attached to a ceiling of one
anygoal [31]

The angle of the pendulum with the vertical is 5.2^{\circ}

Explanation:

As the train decelerates, the bob of the pendulum will feel a force given by

F=ma

where

m = 0.55 kg is the mass of the bob

a=0.9 m/s^2 is the magnitude of the acceleration

In the horizontal direction.

The pendulum will be inclined at an angle \theta from the vertical, so it will be in equilibrium, and therefore the horizontal component of the tension in the string must be equal to the net force F of the previous equation:

T sin \theta = ma (1)

where T is the tension in the string.

We also know that the bob is in equilibrium along the vertical direction: so the vertical component of the tension must be equal to the weight of the bob,

T cos \theta = mg (2)

where g=9.8 m/s^2 is the acceleration of gravity.

Dividing eq.(1) by eq(2), we get:

tan \theta = \frac{a}{g}

And therefore, we find the angle:

\theta=tan^{-1}(\frac{a}{g})=tan^{-1}(\frac{0.90}{9.8})=5.2^{\circ}

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3 0
3 years ago
The horn on a fire truck sounds at a pitch of 350 hz a. what is the perceived frequency when the fire truck is moving toward you
solong [7]

The perceived frequency when the fire truck is moving toward you and away from you will be 370 Hz and 329.59 Hz respectively.

<h3>What is the Doppler effect?</h3>

A sudden change in the frequency due to the distance between the objects and source is explained by the doppler effect.

As the source and observer travel toward each other, the frequency of sound, light, or other waves increases or decreases.

The perceived frequency when the fire truck is moving toward you;

\rm r' = (\frac{v+v_0}{v}) V \\\\ \rm r' = (\frac{343+20}{343}) 350 \\\\ r' =370.4  \  Hz

The perceived frequency when the fire truck is moving away from you;

\rm r' = (\frac{v-v_0}{v}) V \\\\ \rm r' = (\frac{343-20}{343}) 343 \\\\ r' =329.59  \  Hz

Hence, the perceived frequency when the fire truck in cases 1 and 2 will be 370 Hz and 329.59 Hz.

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5 0
1 year ago
an airplanes propeller completes one revolution in 65ms. a)what is the angular speed in rpm? in rad/s?
miss Akunina [59]

-- We already know the rate of revolutions per time ...
it's 1 revolution per 0.065 sec.  We just have to
unit-convert that to 'per minute'.

(1 rev / 0.065 sec) x (60 sec / min) = (1 x 60) / (0.065) = <em>923 RPM</em>  (rounded)
_______________________________

-- 1 revolution = 2π radians

  (2π rad) / (0.065 sec) = (2π / 0.065) = <em>96.66 rad/sec</em>  (rounded)


7 0
3 years ago
A child jumps from a moving sled with a speed of 2.2 m/s and in the
butalik [34]

The initial velocity of the sled will be 7.34 m/sec. V is the initial velocity of the sled.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁)  mass of child = 38 kg

(u₁) is the initial velocity child = 2.2 m/s

(m₂) is the mass of sled = 68 kg

(u₂) is the initial velocity of sled = ?

(v) is the velocity after collision = 5.5 m/s

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

\rm  m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\(38 \times  2.2) + (68 \times V) = 5.5 \times (38+68) \\\\ 83.6 + 68V = 5.5 \times 106 \\\\  83.6 + 68V =583 \\\\ \rm 68\ V= 583 -83.6 \\\\ \rm 68 \ V= 499.4\\\\ V= 7.34 \ m/sec

Hence,the initial velocity of the sled will be 7.34 m/sec.

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4 0
2 years ago
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