Question

How strong is the attractive force between a glass rod with a 0.700μC0.700μC charge and a silk cloth with a –0.600μC–0.600μC charge, which are 12.0 cm apart, using the approximation that they act like point charges?

Answer 1

Answer:

0.2625 N/C

Explanation:

Force of attraction = $\frac{K\timesQ_1\times Q_2}{R^2}$

where Q₁ and Q₂ are charges and R is distance between charges.K is a constant equal to 9 x 10⁹.

= $\frac{9\times10^9\times.7\times10^{-6}\times.6\times10^{-6}}{(12\times10^{-2})^2}$

= 0.2625 N/C