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Alex787 [66]
3 years ago
7

How strong is the attractive force between a glass rod with a 0.700μC0.700μC charge and a silk cloth with a –0.600μC–0.600μC cha

rge, which are 12.0 cm apart, using the approximation that they act like point charges?
Physics
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

0.2625 N/C

Explanation:

Force of attraction = \frac{K\timesQ_1\times Q_2}{R^2}

where Q₁ and Q₂ are charges and R is distance between charges.K is a constant equal to 9 x 10⁹.

= \frac{9\times10^9\times.7\times10^{-6}\times.6\times10^{-6}}{(12\times10^{-2})^2}

= 0.2625 N/C

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3 years ago
An 3.7 lb hammer head, traveling at 5.8 ft/s strikes a nail and is brought to a stop in 0.00068 s. The acceleration of gravity i
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Answer:

31677.2 lb

Explanation:

mass of hammer (m) = 3.7 lb

initial velocity (u) = 5.8 ft/s

final velocity (v) = 0

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acceleration due to gravity (g) 32 ft/s^{2}

force = m x ( a + g )

where

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  • g is the acceleration due to gravity = 32 ft/s^{2}
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       from v = u + at

       a = (v-u)/ t

       a = (0-5.8)/0.00068 = -8529.4 ( the negative sign showa the its decelerating)

we can substitute all required values into force= m x (a+g)

force = 3.7 x (8529.4 + 32) = 31677.2 lb

       

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3 years ago
When the force at the ends of a bar pushes rather than pulls, the bar experiences?
Mariulka [41]

Answer:

I don't know sorry hopefully I can help with something else tho

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It's usually taken from <span>400 to 700 nm.</span> 
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3) Cells arise from pre-existing cells.

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