Was there any choice of answers so i can help or something u have to figure out
Answer: 20 m/s
Explanation: To solve this problem we have to consider the expression of the kinetic energy given by:
Ekinetic=(1/2)*(m*v^2)
then E=0.5*30Kg*(20 m/s)^2=15*400=6000J
Answer:
Solution
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(a) The labelled diagram is shown.
(b) The refractive index of diamond is 2.42. Refractive index of diamond is the ratio of the speed of light in air to the speed of light in diamond.i.e.,
μ=
Speedoflightindiamond
Speedoflightinair
and, the ratio of these velocities is 2.42. i.e., This means that the speed of light in diamond will reduce by a factor of 2.42 as compared to its speed in air. In other words, the speed of light in diamond is
1/2.42
times the speed of light in vacuum.
Explanation:
a) Draw and label the diagram given :
(i) Incident ray
(ii) Refracted ray
(iii) Emergent ray
(iv) Angle of reflection
(v) Angle of deviation
(v) Angle of emergence
(b) The refractive index of diamond is 2.42. What is the meaning of this statement in relation to speed of light?
The red at the bottom is just the holder for the beaker. It’s not apart of the density.