Ask question

Ask question

All categories

3 years ago

12

When light travels through a small hole, it appears to an observer that the light spreads out, blurring the outline of the hole.

Does this observation support the theory of light as a wave, or light being made of particles? Explain.

1 answer:

Scilla [17]3 years ago

4 0

wave theory

this observation supports the theory of light as a wave

You might be interested in

Which state of matter has a definite volume but no definite shape

a_sh-v [17]

The answer is liquid.

6 0

3 years ago

A plane traveling 40 m/s drops a box from a height of 186 m. Where does the box strike the ground relative to the point directly

Arte-miy333 [17]

Answer:the horizontal velocity is 40

Explanation:

8 0

3 years ago

When the thermal energy of a material decreases, _____.

Pani-rosa [81]

The surrounding environment cool off is the answer

8 0

3 years ago

Read 2 more answers

an object has a momentum of 250 kg m/s what would be the momentum of an object that has half of the mass and going at the same v

Romashka-Z-Leto [24]

The momentum of the second object is 125 kg m/s

Explanation:

The momentum of an object is given by

$p=mv$

where

m is the mass of the object

v is its velocity

For the object in this problem,

$p = 250 kg m/s$

And its mass is m and its velocity is v.

The second object has a mass of $m' = \frac{m}{2}$ and same velocity v, so its momentum is

$p'=m'v = (\frac{m}{2})v=\frac{1}{2}(mv)=\frac{1}{2}p$

So, the second object has a momentum that is half of the momentum of the first object, therefore it is:

$p'=\frac{1}{2}(250)=125 kg m/s$

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

3 0

3 years ago

An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If y

Xelga [282]

Answer:

The fraction of the protons would have no electrons $=1.88\times 10^{-10}$

Explanation:

We are given that

Amoeba has total number of protons= $1.00\times 10^{16}$

Net charge, Q=0.300pC

Electrons are fewer than protons= $1.88\times 10^6$

We have to find the fraction of protons would have no electrons.

The fraction of the protons would have no electrons

= $\frac{Fewer\;electrons}{Total\;protons}$

The fraction of the protons would have no electrons

= $\frac{1.88\times 10^{6}}{1.00\times 10^{16}}$

$=1.88\times 10^{-10}$

Hence, the fraction of the protons would have no electrons $=1.88\times 10^{-10}$

6 0

3 years ago