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2 answers:
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Answer:
(a) If r is any rational number and s is any irrational number, then r/s is rational
(b) The statement is false when r is 0
Step-by-step explanation:
Given
rational number
irrational number
irrational number
Solving (a): The negation
To get the negation of a statement, we only need to negate the end result
In other words, the number type of r and s will remain the same, but r/s will be negated.
So, the negation is:
rational number
irrational number
rational number
Solving (b): When r/s is irrational is false
Given that:
irrational number
Set r to 0
So:
-- rational
<em>Hence, the statement is false when r is 0</em>
Answer:
f(x) = -2x + 7, when x > 1
f(x) = 4x + 1 when x ≤ 1
Step-by-step explanation:
The right side graph passe through points (1,5) and (2,3).
Hence, the equation of the line
⇒ (y - 5) = 2(1 - x)
⇒ y - 5 = 2 - 2x
⇒ y = -2x +7.......... (1)
Now, the left side graph passes through points (1,5) and (0,1)
Therefore, the equation of the graph will be
⇒ y - 5 = 4(x - 1)
⇒ y = 4x + 1 ........ (2)
Hence, the equation (1) gives the function in the right side of the given graph which does not include the point (1,5) and extends to the right from this point.
Therefore, f(x) = -2x + 7, when x > 1 (Answer)
Again, equation (2) gives the function in the left side of the given graph which includes the point (1,5) and extends to the left from this point.
Therefore, f(x) = 4x + 1 when x ≤ 1 (Answer)