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KIM [24]
3 years ago
11

Let

Mathematics
1 answer:
kow [346]3 years ago
6 0

Answer:

can write it again soon as you can do it again

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When angles complementary,the sum of their mesures is 90 degrees. Two complementary angles have measures of 2x-10 degrees and 3x
kykrilka [37]

Answer:

34 degrees and 56 degrees

Step-by-step explanation:

As the two given angles are complementary,

2x-10+3x-10=90

5x-20=90

5x=90+20=110

x=110/5=22

x=22

Now each angle

2x-10=2*22-10=34 degrees

and

3x-10=3*22-10= 56 degrees

4 0
4 years ago
What is -40 divided by -4
sergiy2304 [10]
The Answer Is 10. Because We Know That A Negative Number Divided By A Negative Number Will Give You A Positive Number As Your Answer So -40 Divided By -4 Is 10.
5 0
3 years ago
Read 2 more answers
Simply the radical 125
Alja [10]

Answer:

The answer is 5 √5

Step-by-step explanation:

6 0
3 years ago
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A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

7 0
3 years ago
What are the relationship between the legs and hypotenuse of 45 45 90
Semenov [28]
The relationship between the legs and hypotenuse of a 45 45 90 triangle can be written as:

1: 1: square root 2
7 0
3 years ago
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