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3 years ago

Let

Mathematics

1 answer:

kow [346]3 years ago

6 0

Answer:

can write it again soon as you can do it again

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Otrada [13]

Answer:

2 2/5 or 12/5 (if u want it in improper fraction) but both works!

Step-by-step explanation:

8 0

3 years ago

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I begin with a three-digit positive integer. I divide it by 9 and then subtract 9 from the answer. My final answer is also a thr

erica [24]

Answer:

Step-by-step explanation:

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3 years ago

Aa glass blower made 342 marbles. He wants to place an equal number of marbles in each of 9 boxes how many marblws will be place

prisoha [69]

38 marbles. 342 divided by 9 = 38.

6 0

3 years ago

Ian and his friends are renting a cabin that charges an initial fee plus a rate per night. The relationship between the cost and

Brut [27]

Answer:

Cost per night: 75

Equation: $y = 75x + 50$

Step-by-step explanation:

An equation to represent the situation can be written in the slope-intercept form, $y = mx + b$ , where,

m = slope of the graph, which is the rate per night.

b = y-intercept, which is the initial fee. It is the point where the line intercepts the y-axis.

Let's find m, using two points on the line, (2, 200) and (4, 350)

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{350 - 200}{4 - 2} = \frac{150}{2} = 75$

✅The cost per night = 75

y-intercept, b, = 50. The line intercepts the y-axis at y = 50, when x = 0.

Substitute m = 75, and b = 50 into $y = mx + b$ .

✅The equation would be:

$y = 75x + 50$

6 0

3 years ago

Draw a right triangle with one leg value is 4 and the other leg value is 3. Use the triangle to find the exact values of the six

Nina [5.8K]

Step-by-step explanation:

Draw a right triangle with one leg value is 4 and the other leg value is 3

The triangle is attached below

To find hypotenuse , use Pythagorean theorem

$c^{2} =a^{2} +b^{2} \\c^{2} =3^{2} +4^{2} \\\\c^{2} =25 \\\\c=\sqrt{25} =5$

opposite side = 4, adjacent side =3 and hypotenuse = 5

Apply trigonometric ratios

$sin(A)=\frac{opposite}{hypotenuse}=\frac{4}{5}$

$cos(A)=\frac{adjacent}{hypotenuse}=\frac{3}{5}$

$tan(A)=\frac{opposite}{adjacent}=\frac{4}{3}$

$cosec(A)=\frac{hypotenuse}{opposite}=\frac{5}{4}$

$sec(A)=\frac{hypotenuse}{adjacent}=\frac{5}{3}$

$cot(A)=\frac{adjacent}{opposite}=\frac{3}{4}$

4 0

4 years ago