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AfilCa [17]
3 years ago
5

What is the answer... I need lots of help

Mathematics
2 answers:
barxatty [35]3 years ago
6 0
9 / 1/6=54
When dividing fractions, you use keep, change, flip.
Keep 9
Change / to *
Flip / to 6/1
Now, you have 9/1 * 6/1=54

Hope this helped☺☺
dangina [55]3 years ago
6 0
If what that say is 9 ÷ 1/2
Then the answer would be 18
If this helped pls mark as brainliest
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A town's public works department has ordered sand to spread on roadways during the upcoming winter snows. The delivered sand for
ira [324]

Answer:

1256 cubic yards of sand.

Step-by-step explanation:

In this question we have to find the volume of cone formed by sand.

Height of the cone is = 36 feet

Radius of the cone = 60/2 =30 feet.

Now we know the formula of volume of cone v = π r² (h/3)

By putting the values of r and h we can get the volume of sand to spread.

Volume = π×(30)²×(36/3) = 3.14×900×12 feet³

              = 33912 feet³

Now we will convert feet³ to cubic yards

Since 1 cubic feet = .037037 cubic yards

therefore 33912 cubic feet = 33912×.037 = 1256 cubic yards.

So the answer is 1256 cubic yards of sand has the department received.

5 0
3 years ago
PLZ, HELP WILL GET BRAINLIEST AND A LOT OF POINTS.
TEA [102]

Answer:

y=2(4^x)

Step-by-step explanation:

if you notice, all the y-values are multiplied by 4 for each x-value. this means 4 is raised to the power of x. however, when you plug this in, you realize that the value produced is only half the actual y-values, so you multiply this whole thing by 2.

y=2(4^x)

4 0
3 years ago
Read 2 more answers
Write and solve the proportion.
Nonamiya [84]

Answer: I believe it would be 15.42

Step-by-step explanation:

5 0
4 years ago
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What is the probability of drawing the compliment of a king or a
inna [77]

Answer:

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

n( E_{1} ) = 4 _{C_{1} }  = 4

Let E₂ be the event of the card drawn being a queen

n( E_{2} ) = 4 _{C_{1} }  = 4

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability  of drawing of a king or a  queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

                 = \frac{4}{52} + \frac{4}{52}

P( E₁ U E₂ ) = \frac{8}{52}

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards

P(E_{1}UE_{2})  ^{-} = 1- P(E_{1} U E_{2} )

P(E_{1}UE_{2})  ^{-} = 1- \frac{8}{52}

P(E_{1}UE_{2})  ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

5 0
3 years ago
What is -10p+10 equal
sashaice [31]

Answer:

0

Step-by-step explanation:

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3 years ago
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