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MaRussiya [10]
3 years ago
11

Line l is defined by the equation y – 5x = 4 and line w is defined by the equation 10y + 2x + 20 = 0. if line k does not interse

ct line l, what is the degree measure of the angle formed by line k and line w? (assume that all lines lie in one coordinate plane.)
Mathematics
1 answer:
Sliva [168]3 years ago
7 0
Slope of line l (m1)=5
Slope of line w(m2)=-1/5
Since,m1×m2=-1 , line 'l' and 'w' are perpendicular.
Since line 'k' doesn't intersect line 'l' ,they must be parallel b'coz they are in the same plane as well.
Here, 'l' is perpendicular to 'w' and parallel to 'k'....so w and k must be perpendicular to each other.
It can be proven:
Since l and k are parallel, their slopes are equal.
So, slope of k (m3)=5
Since m3×m2=-1 ,w and k are perpendicular.
Hence, angle between w and k is 90°
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4. Lizette said this is correct. Is she right? Explain your answer to this question for
Maslowich

Answer:

Please check the explanation!

Step-by-step explanation:

Given the expression what Lizzet said was correct

6^3\times \:\:3^6=18^8

No, she is not right. Let me solve the expression

Let us solve the expression

6^3\times \:\:3^6

=\left(3\times \:2\right)^3\times \:3^6

\mathrm{Apply\:exponent\:rule}:\:\:\:\left(ab\right)^c=a^cb^c

=3^3\times \:2^3\times \:3^6          ∵  \left(3\times \:2\right)^3=3^3\times \:2^3

\mathrm{Apply\:exponent\:rule}:\:\:a^b\times \:\:a^c=a^{b+c}

=2^3\times \:3^{3+6}                 ∵  3^3\times \:3^6=\:3^{3+6}

=2^3\times \:3^9

Therefore, the correct expression will be:

6^3\times \:\:3^6=2^3\times \:\:3^9

which can be further simplified such as:

6^3\times \:\:3^6=2^3\times \:\:3^9

             =8\times \:19683

             =157464

6 0
3 years ago
−4x−2y x−2y ​ =−2 =9 ​
fenix001 [56]
Dy\dx=-2+y/x+1 is the answer I think
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3 years ago
GIVING BRAINLIEST!!!!
pochemuha

Answer:

It is a function

Step-by-step explanation:

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