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EastWind [94]
3 years ago
5

Calculate the first, second, and third quartiles of the following sample. 5 8 2 9 5 3 7 4 2 7 4 10 4 3 5

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

3 ; 4.5 ; 7.25

Step-by-step explanation:

Given the sample :

8 2 9 5 3 7 4 2 7 4 10 4 3 5

Calculate, the first, second, and third quartiles

Arranging the data in ascending order :

2, 2, 3, 3, 4, 4, 4, 5, 5, 7, 7, 8, 9, 10

First quartile :

Q1 = [(n + 1) /4]th value

n = 14

Q1 = [(14 + 1) /4]th = (15/4)th = 3.75 value

Taking the average of the 3rs and 4th observation:

(3 +3) / 2 = 3

Second quartile :

Q2 = [2(n + 1) /4]th value

Q2 = 2(15)/4 = (30/4)th value

Q2 = 7.5 ; taking the 7th and 8th value

Q2 = (4 +5) /2 = 9/2 = 4.5

Q3 = [3(n + 1) /4]th value

Q2 = 3(15)/4 = (45/4)th value

Q2 = 11.25 ; taking the 11th

Q2 = 7 + 0.25 = 7.25

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Answer:

-2x^{2}-12x-26

Step-by-step explanation:

(x+3)^2 = x^2+6x+9

-2(x^2+6x+9)-8

-2x^2-12x-18-8

-2x^2-12x-26

8 0
4 years ago
Consider the following system of equations:
jenyasd209 [6]
Y=-x+10
2x+3(-x+10)=45
2x+-3x+30=45
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4 0
3 years ago
Ninety six passengers rode a train. Tickets for regular coach seats are $114. Tickets for sleeper car seats are $295. The receip
MrRa [10]
C = amount of folks buying coach tickets
s = amount fo folks buying sleeper car tickets

we know the train had a total of 96 passengers, so, whatever "c" and "s" are
c + s = 96

we know all tickets sold for all 96 passengers was 19994, so, if "c" folks rode coach, each ticket is 114, thus 114*c is  how much money was from couch, or 114c

if "s" folks rode the sleeper car, we know each ticket is 295 each, so 295*s is how much money was from the sleeper car

we also know, the total for all tickets is 19994

thus    114c + 295s = 19994

thus   \bf \begin{cases}
c+s=96\implies \boxed{s}=96-c\\
114c+295s = 19994\\
----------\\
114c+295\left( \boxed{96-c} \right)=19994
\end{cases}

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5 0
3 years ago
A 5.5 ounce breadstick weighs the same as 16
givi [52]

Answer: top right

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8 0
3 years ago
WORTH 12 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! HELP ASAP
IrinaK [193]

Answer:

\large\boxed{S.A.=1,000\ u^2}

Step-by-step explanation:

We have two congruent right triangles and three rectangles.

First, calculate the length of the hypotenuse using the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=8,\ leg=15,\ hypotenuse=h

Substitute:

h^2=8^2+15^2\\\\h^2=64+225\\\\h^2=289\to h=\sqrt{289}\\\\h=17

The formula of an area of a right triangle:

A_t=\dfrac{(leg)(leg)}{2}

Substitute:

A_t=\dfrac{(8)(15)}{2}=(4)(15)=60

The formula of an area of a rectangle:

A=wl

w - width

l - length

Rectangle 1:

w = 15, l = 22

A_1=(15)(22)=330

Rectangle 2:

w = 17, l = 22

A_2=(17)(22)=374

Rectangle 3:

w = 8, l = 22

A_3=(8)(22)=176

The Surface Area of the triangular prism:

S.A.=2A_t+A_1+A_2+A_3

Substitute:

S.A.=2(60)+330+374+176=1,000

8 0
4 years ago
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