PLEASE HELP ME!! What is the equation of the line in slope-intercept form?
2 answers:
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Using the unit circle, you can visualise the secant as follows:
- Draw the vertical line passing trough (1,0)
- Extend the radius until it meets this line at point P
- The length of OP is the secant of your angle.
Since -90 means that the radius points downwards, it means that the radius is vertical as well, and thus it never meets the vertical line through (1,0).
Thus, the secant is not defined at -90.
In fact, if we switch back to the function notation, we can confirm this claim, since we have
which is undefined.
Answer:
Step-by-step explanation:
The given line is in slope-intercept form,
y = mx + b,
where m is the slope.
The slope of the given line is 1/3, so m = 1/3.
Parallel lines have equal slopes, so the slope of the parallel line is also 1/3.
y = 1/3 x + b
Now we can find the equation of the parallel line through point (6, 3) by using the given point's coordinates for x and y and solving for b.
3 = (1/3)(6) + b
3 = 2 + b
b = 1
Equation: