.04(2x)+.03(x)+.05(500+x)=2025
.08x+.03x+.05x+25=2025
.16x+25=2025
.16x=2000
x=12500
She has 2x invested at 4%, so she had $25000.00 invested at 4%.
Answer:
B) -3.464
Step-by-step explanation:
∫₀³ g'(x) cos²(2g(x) + 1) dx
Using u substitution:
u = 2g(x) + 1
du = 2g'(x) dx
½ du = g'(x) dx
When x = 0, u = 11.
When x = 3, u = -3.
½ ∫₁₁⁻³ cos²(u) du
You can use a calculator to solve this, or you can evaluate algebraically.
Use power reduction formula:
½ ∫ (½ + ½ cos(2u)) du
¼ ∫ du + ¼ ∫ cos(2u) du
¼ ∫ du + ⅛ ∫ 2 cos(2u) du
¼ u + ⅛ sin(2u) + C
Evaluating from u = 11 to u = -3:
[¼ (-3) + ⅛ sin(-6) + C] − [¼ (11) + ⅛ sin(22) + C]
-⁷/₂ + ⅛ sin(-6) − ⅛ sin(22)
−3.464
A.4
hope this helped:)
plz mark brainliest
Answer:
The most tickets were written on Saturday .On Saturday 325 tickets were issued
Step-by-step explanation:
The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by
Where x represents the number of days after Sunday
T(x) represents the number of traffic tickets issued.
Sunday = x=0
Monday = x=1
Tuesday = x=2
Wednesday = x=3
Thursday = x =4
Friday = x=5
Saturday = x=6
Substitute x= 0
On Sunday 37 tickets were issued
Substitute x= 1
On Monday 115 tickets were issued
Substitute x= 2
On Tuesday 181 tickets were issued
Substitute x= 3
On Wednesday 235 tickets were issued
Substitute x= 4
On Thursday 277 tickets were issued
Substitute x= 5
On Friday 307 tickets were issued
Substitute x= 6
On Saturday 325 tickets were issued
Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued