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sattari [20]
3 years ago
13

The average number of traffic tickets issued in a city on any given day

Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:

The most tickets were written on Saturday .On Saturday 325 tickets were issued

Step-by-step explanation:

The average number of traffic tickets issued in a city on any given day  Sunday-Saturday  can be approximated by

T(x) = -6x^2 + 84x + 37

Where  x represents the number of days after Sunday

T(x) represents the number of traffic tickets issued.

Sunday = x=0

Monday = x=1

Tuesday = x=2

Wednesday = x=3

Thursday = x =4

Friday = x=5

Saturday = x=6

Substitute  x= 0

T(x) = -6x^2 + 84x + 37\\T(x) = -6(0)^2 + 84(0) + 37\\T(x)=37

On Sunday 37 tickets were issued

Substitute  x= 1

T(x) = -6x^2 + 84x + 37\\T(x) = -6(1)^2 + 84(1) + 37\\T(x)=115

On Monday 115 tickets were issued

Substitute  x= 2

T(x) = -6x^2 + 84x + 37\\T(x) = -6(2)^2 + 84(2) + 37\\T(x)=181

On Tuesday 181 tickets were issued

Substitute  x= 3

T(x) = -6x^2 + 84x + 37\\T(x) = -6(3)^2 + 84(3) + 37\\T(x)=235

On Wednesday 235 tickets were issued

Substitute  x= 4

T(x) = -6x^2 + 84x + 37\\T(x) = -6(4)^2 + 84(4) + 37\\T(x)=277

On Thursday 277 tickets were issued

Substitute  x= 5

T(x) = -6x^2 + 84x + 37\\T(x) = -6(5)^2 + 84(5) + 37\\T(x)=307

On Friday 307 tickets were issued

Substitute  x= 6

T(x) = -6x^2 + 84x + 37\\T(x) = -6(6)^2 + 84(6) + 37\\T(x)=325

On Saturday 325 tickets were issued

Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued

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Simplify 30-(18/9+3) plz hurry
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25

Step-by-step explanation:

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If nkf ~ lzf, find nf, please help me with this it’s due tmr!!!!
Ratling [72]

Answer:

NF = 25

Step-by-step explanation:

Since ∆NKF ~ ∆LZF, the ratio of their corresponding side lengths would also be the same.

This means that:

KF/ZF = NF/LF

KF = x + 3

ZF = 4

NF = 15 + x + 3 = x + 18

LF = x + 3

Plug in the values into the equation

(x + 3)/4 = (x + 18)/(x + 3)

Cross multiply

(x + 3)(x + 3) = (x + 18)(4)

x² + 3x + 3x + 9 = 4x + 72

x² + 6x + 9 = 4x + 72

x² + 6x + 9 - 4x - 72 = 0

x² + 2x - 63 = 0

Factorize to find x

x² + 9x - 7x - 63 = 0

x(x + 9) -7(x + 9) = 0

(x + 9)(x - 7) = 0

x + 9 = 0 or x - 7 = 0

x = -9 or x = 7

We'd use the positive value of x, which is 7.

Therefore, x = 7.

✅NF = 15 + (x + 3)

Plug in the value of x

NF = 15 + (7 + 3) = 15 + 10

NF = 25

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2 years ago
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