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garri49 [273]
3 years ago
11

- 16(x - 2)² – 25=0​

Mathematics
1 answer:
Amanda [17]3 years ago
8 0

Answer:

x=2±16i\sqrt{73}

Step-by-step explanation:

1.) Using the PEMDAS distribute the (x-2)^{2} using the FOIL method

(x-2)^2= x^2-4x+4

2.) Distribute the -16 to ((x-2)^2= x^2-4x+4)

-16(x^2-4x+4)= -16x^2+64x-64

3.) Add the -25 to the equation

(-16x^2+64x-64)-25=-16x^2+64x-89=0

4.) Since this isn't factor-able, you must use the quadratic formula,

\frac{(-b (+ or -) \sqrt{(b^2-4ac)}}{2a} and distrubute the numbers

a=-16 b=64 and c=-89

5.) Simplify the radical by finding the factors of -18688 that has a perfect root as one of the factors (which is -256 and 73).

\sqrt{-18688} =\sqrt{-256*73} =16i\sqrt{73}

6.)Simplify the fraction

\frac{-64(+ or -)16i\sqrt{73} }{-32} ={2}(+ or -)16i\sqrt{73}

7.) Your two roots are:

{2}(+ or -)16i\sqrt{73}

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Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
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Answer:

a) 0.5.

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c) 0.8413

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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In this problem, we have that:

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This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

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(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

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In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

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Z = \frac{X - \mu}{\sigma}

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This is 1 subtracted by the pvalue of Z when X = 5.7.

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This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

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Z = -5

Z = -5 has a pvalue of 0.

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125.06 million dollars, if you can use the number in the question.
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