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Tema [17]
3 years ago
9

What is the expected value of an original Investment of $3,000 that has a 10% chance of ending up with a value of $2,000, an 80%

chance of ending up with a value of $3,500, and a 10% chance of ending up with a value of $4,000?
A $6,000

B. $3,500

C $3,400

D. $3,250

E $3,000
Mathematics
1 answer:
Sloan [31]3 years ago
3 0

Answer:

Option C.

Step-by-step explanation:

The original value of  Investment = $3,000

It has a 10% chance of ending up with a value of $2,000.

Chances of loss of $1000 = 0.1

It has a 80% chance of ending up with a value of $3,500.

Chances of profit of $500 = 0.8

It has a 10% chance of ending up with a value of $4,000.

Chances of profit of $1000 = 0.1

Expected change in the value of investment is

Change=(-\$1000)(0.1)+(\$500)(0.8)+(\$1000)(0.1)

Change=-\$100+\$400+\$100

Change=\$400

The expected change in the value of the investment is $400.

The expected value of an original Investment of $3,000 is

\$3000+\$400=\$3400

Therefore, the correct option is C.

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Answer:

see explanation

Step-by-step explanation:

Check the value of the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real

• If b² - 4ac = 0 roots are real and equal

• If b² - 4ac < 0 then roots are not real

given (x - a)(x - b) = k² ( expand factors )

x² - bx - ax - k² = 0 ( in standard form )

x² + x(- a - b) - k² = 0

with a = 1, b = (- a - b), c = -k²

b² - 4ac = (- a - b)² + 4k²

For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0

Hence roots of the equation are always real for a, b, k ∈ R


           

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What we know:      

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(Also, 3^2=9)

What we need to solve:

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