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mr_godi [17]
3 years ago
15

What is the area of the figure

Mathematics
2 answers:
Naily [24]3 years ago
7 0
The answer is 1020 m long
guajiro [1.7K]3 years ago
4 0

Answer:

963.73\ m^{2}

Step-by-step explanation:

Area of a triangle + area of a semicircle.

A_{t} = \frac{a * h}{2} = \frac{30 * 34}{2} = 510\ m^{2} \\\\A_{sc} = \frac{r^{2} \pi}{2} = \frac{17^{2} \pi }{2} = 453.73\ m^{2}

A = A_{t} + A_{sc}  = 963.73\ m^{2}

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I think it would be 87.5 as an average between 85 and 90.

Step-by-step explanation:

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Question 9(Multiple Choice Worth 1 points) (01.06 LC) Solve x -5y = 6 for x.​
vladimir1956 [14]
The answer is x = 6 + 5y
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Keisha counted 458cars and Simon counted 509cars. Estimate how many more cars simon counted by rounding to the nearest ten and t
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The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

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Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

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⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

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So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

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3 years ago
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A football player forces at least 1 turnover in 27.5 percent of the games he plays. If the player plays in 57 games, in how many
Nataly_w [17]

Answer:

2 times. (2.0727272727)

Step-by-step explanation:

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About two times.

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