There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
At 1/8 of a gallon you can mow 2 1/4 so for 1 gallon just multiply 2 1/4 by 8
16+2 is 18
Answer:
74.4
Step-by-step explanation:
It is already rounded to the nearest tenth of a percent. If it was rounded to the nearest percent it'd be 74%.
Answer: I would say Side-Angle-Side
Step-by-step explanation: