Answer:
x = 0 , x = 9
Step-by-step explanation:
to find the zeros let f(x) = 0 , that is
x(x - 9) = 0
equate each factor to zero and solve for x
x = 0
x - 9 = 0 ⇒ x = 9
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
They repeat by adding that same number again and again
Answer:
-37/5= y
x=11/5
Step-by-step explanation:
4x-3y=31
-3y=-4x+31 regroup it to match the other
-2 y=(2x-3)(-2) multiply by -2 to get -4x
-3y=-4x+31
-2y=-4x+6 adding
-5y=37 divide
-37/5= y
4x-3(-37/5)=31
x=11/5
