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Aleonysh [2.5K]
4 years ago
15

What is 5 1/2 divided by 3/4?HELP please I need immediately!!

Mathematics
2 answers:
melamori03 [73]4 years ago
6 0
<span> 5 1/2 divided by 3/4? = 11/2 / 3/4
= 11/2 * 4/3
= 44/6 = 7 2/6 = 7 1/3
 SO ANSWER IS </span>7 1/3
Levart [38]4 years ago
4 0
5\frac{1}{2}:\frac{3}{4}=\frac{5\cdot2+1}{2}:\frac{3}{4}=\frac{11}{2}\cdot\frac{4}{3}=\frac{11}{1}\cdot\frac{2}{3}=\frac{11\cdot2}{3}=\boxed{\frac{22}{3}=7\frac{1}{3}}
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I need help on question 2 i need the simplified answer and the restrictions
Anastaziya [24]

Answer:

x cannot be 5 or -3.

\frac{x+5}{x+3}

Step-by-step explanation:

The restrictions for a fraction is that the bottom cannot be 0.

So if we find when the bottom is 0 we have found the values that x cannot be.

Let's solve x^2-2x-15=0.

Since the coefficient of x^2 is 1 all we have to do is find two numbers whose product is -15 and whose sum is -2.

Those numbers are -5 and 3 since (-5)(3)=-15 and (-5)+(3)=-2.

So the factored form of the equation is:

(x-5)(x+3)=0

This means either x-5=0 or x+3=0.

We do have to solve both.

x-5=0 can be solved by adding 5 on both sides.

x-5+5=0+5

x+0=0+5

x=5

x+3=0 can be solved by subtracting 3 on both sides.

x+3-3=0-3

x+0=0-3

x=-3

So x can be any number except x=5 or x=-3.

We already factored the bottom as (x-5)(x+3).

The top is a difference of squares, x^2-a^2,

which can be factored as (x-a)(x+a).

So the top factors as (x-5)(x+5).

The fraction can then be written as:

\frac{x^2-25}{x^2-2x-15}=\frac{(x-5)(x+5)}{(x-5)(x+3)}

This can further simplified assuming x is not 5 we can write it as \frac{x+5}{x+3}.  I canceled the common factor of (x-5).

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Step-by-step explanation:

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