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givi [52]
3 years ago
15

Can somebody help with this question

Mathematics
1 answer:
AURORKA [14]3 years ago
5 0
A^2+b^2=c^2
So
c^2-a^2=b^2
34^2-30^2=256
√256=16in
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Use a graphing calculator to approximate the vertex of the graph of the parabola defined by the following
gregori [183]

Answer:

  (1/4, 5 7/8)

Step-by-step explanation:

The vertex is the extreme point of the graph. Here, it is a minimum.

For this quadratic function, a graphing calculator can tell you exactly what the vertex is. (No approximation is required.)

__

The graphing calculator in the attachment shows the vertex is ...

  (0.25, 5.875) = (1/4, 5 7/8)

8 0
2 years ago
Which term describes the set of all possible output values for a function?
Firdavs [7]

The <em><u>correct answer</u></em> is:

C. Range

Explanation:

The definition of domain is the set of all possible input values, or x-values, of a function.

The definition of range is the set of all possible output values, or y-values, of a function.

3 0
3 years ago
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Answer the questions from the picture <br> Step by step
andre [41]

Answer:

6 = 4 mins

Step-by-step explanation:

you have to take 200 and 50 and divide them

200 divided by 50 =4 and you have to tack mins to the end of it

id_k how many class rooms for number 5

and 7 i dk how many weeks there are therefore i cant solve them

7 0
2 years ago
HJ
Olin [163]

Answer:

19 degrees

Step-by-step explanation:

From the question given

The interior angles are x+12 and x - 3

Exterior angle is <IJK = 5x-6

Using the rule that states that the sum of interior angle of a triangle is equal to the exterior

<JHI + <HIJ = <IJK

x+12 + x-3 = 5x - 6

2x+9 = 5x -6

2x - 5x = -6-9

-3x = -15

x = -15/-3

x = 5

Get <IJK

Recall that <IJK = 5x - 6

<IJK = 5(5) - 6

<IJK = 25-6

<IJK = 19 degrees

Hence the measure of <IJK is 19 degrees

8 0
3 years ago
Determine if each of the following sets is a subspace of Pn, for an appropriate value of n.
snow_tiger [21]

Answer:

1) W₁ is a subspace of Pₙ (R)

2) W₂ is not a subspace of Pₙ (R)

4) W₃ is a subspace of Pₙ (R)

Step-by-step explanation:

Given that;

1.Let W₁ be the set of all polynomials of the form p(t) = at², where a is in R

2.Let W₂ be the set of all polynomials of the form p(t) = t² + a, where a is in R

3.Let W₃ be the set of all polynomials of the form p(t) = at² + at, where a is in R

so

1)

let W₁ = { at² ║ a∈ R }

let ∝ = a₁t² and β = a₂t²  ∈W₁

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t²) + c₂(a₂t²)

= c₁a₁t² + c²a₂t²

= (c₁a₁ + c²a₂)t² ∈ W₁

Therefore c₁∝ + c₂β ∈ W₁ for all ∝, β ∈ W₁  and scalars c₁, c₂

Thus, W₁ is a subspace of Pₙ (R)

2)

let W₂ = { t² + a ║ a∈ R }

the zero polynomial 0t² + 0 ∉ W₂

because the coefficient of t² is 0 but not 1

Thus W₂ is not a subspace of Pₙ (R)

3)

let W₃ = { at² + a ║ a∈ R }

let ∝ = a₁t² +a₁t  and β = a₂t² + a₂t ∈ W₃

let c₁, c₂ be two scalars

c₁∝ + c₂β = c₁(a₁t² +a₁t) + c₂(a₂t² + a₂t)

= c₁a₁t² +c₁a₁t + c₂a₂t² + c₂a₂t

= (c₁a₁ +c₂a₂)t² + (c₁a₁t + c₂a₂)t ∈ W₃

Therefore c₁∝ + c₂β ∈ W₃ for all ∝, β ∈ W₃ and scalars c₁, c₂

Thus, W₃ is a subspace of Pₙ (R)

8 0
3 years ago
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