So.. let's say ∡AGB and ∡BGC are say "a" units wide, and ∡CGD and ∡DGE are "b" units wide
notice the picture below
all angles added up together, will make up just a flat line, or 180°
now, notice in the picture, the ∡BGD is really just " a + b " wide, notice the green angle in the picture of ∡BGD, well, we know what a + b is
Answer:
Step-by-step explanation:
A)1st pair: ∠HKJ ,∠JKG 2nd pair: ∠HKE,∠EKF
B)Verticle angle:∠HKE and ∠GKF
C) 4x+5+41=180
4x+46=180
4x=134
x=33.5
D)4x+36=90
4x=90-36
4x=54
x=13.5
E) x+x-4=180
2x=184
x=92
Answer:
It's not correct
Because
Ratio is the comparison of two quantities having same units
So this ratio can't be taken
Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
Answer:
<u>585/4</u> or <u>146.25</u>
Step-by-step explanation:
10 x 6 1/2 x 2 1/4
10 x 13/2 x 9/4
5 x 13 x 9/4
65 x 9/4
<u>585/4 = 146.25</u>
