AB (y=3) and CD (y=6) are parallel, but different lengths. The figure is a trapezoid. A diagram shows it to be an isosceles trapezoid.
0002077 in scientific notation
1 answer:
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Answer:
Step-by-step explanation:
We can write the following system of equations:
Adding both equations together, we isolate and get:
Plugging in any of the equations, we can solve for
:
Verify that the solution pair works
Therefore, the two numbers are .
These array of numbers shown above are called matrices. These are rectangular arrays of number that are arranged in columns and rows. It is mostly useful in solving a system of linear equations. For example, you have these equations
x+3y=5
2x+y=1
x+y=10
In matrix form that would be
![\left[\begin{array}{ccc}1&3&5\\2&1&1\\1&1&10\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%265%5C%5C2%261%261%5C%5C1%261%2610%5Cend%7Barray%7D%5Cright%5D%20)
where the first column are the coefficients of x, the second column the coefficients of y and the third column is the constants, When you multiple matrices, just multiply the same number on the same column number and the same row number. For this problem, the solution is
![\left[\begin{array}{ccc}3*2&0*8\\2*0.6&-1*3\end{array}\right] = \left[\begin{array}{ccc}6&0\\1.2&-3\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%2A2%260%2A8%5C%5C2%2A0.6%26-1%2A3%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%260%5C%5C1.2%26-3%5Cend%7Barray%7D%5Cright%5D%20)
x+3y=5
2x+y=1
x+y=10
In matrix form that would be
where the first column are the coefficients of x, the second column the coefficients of y and the third column is the constants, When you multiple matrices, just multiply the same number on the same column number and the same row number. For this problem, the solution is