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anyanavicka [17]
4 years ago
10

0002077 in scientific notation

Mathematics
1 answer:
LekaFEV [45]4 years ago
7 0
3 x 10 3^   The three up sign means to the third power
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If anna is 11 years older than Robert and robert is 2 years younger than sara david is 8 years older than Sara how old is everyo
grigory [225]

Answer:

The information given is not enough to determine their ages explicitly, so, here their ages are given in terms of Anna's age, which is the best that could be determined.

Anna's age = x years

Robert's age = (x - 11) years

Sara's age = (x - 9) years

David's age = (x - 1) years

Step-by-step explanation:

Let Anna be x years old.

Anna's age = x

Because Anna is 11 years older than Robert, we can say Robert's age is Anna's age minus 11.

Robert = x - 11

But Robert is 2 years younger than Sara, we can say Sara's age is Robert's age plus 2

Sara = (x - 11) + 2

= x - 9

David is 8 years older than Sara, we can say David's age is Sara's age plus 8.

David = (x - 9) + 8

= x - 1

4 0
3 years ago
Need help really hard and confusing
Stels [109]
To name 3 decimals between .55 and .56 just add another number to .55 For instance, .551 and .552 and
.553 are Three decimals between .55 and .56. If we start off with .55 we will not get to .56 untill .559 flips.
So
.550
.551
.552
.553
.554
.555
.556
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.56
5 0
3 years ago
Can someone help me with these two problems?
Sav [38]

Answer:

  C.  38°

  D.  30°

Step-by-step explanation:

The relevant relation in both cases is the inscribed angle measures half the measure of the arc it intercepts.

__

C. Angle TSQ intercepts arc TQ, so the measure of arc TQ is 2(86.5°) = 173°. The measure of arc TR is the difference between the measures of arcs TQ and RQ, so is ...

  arc TR = 173° -135° = 38°

__

D. Inscribed angle PQR intercepts arc PR, so is half its measure.

  angle PQR = 60°/2 = 30°

6 0
3 years ago
A student claims that 2i is the only imaginary root of a polynomial equation that has real coefficients. Explain the student's m
____ [38]

Answer:

The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i

Step-by-step explanation:

1) This claim is mistaken.

2) The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

a_{0}x^{n}+a_{1}x^{2}+....a_{1}x+a_{0}

For example:

3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

\Delta < 0\\b^{2}-4*a*c

We'll have <em>n </em>different complex roots, not necessarily 2i.

For example:

Taking 3 polynomial equations with real coefficients, with

\Delta < 0

-4x^2-x-2=0 \Rightarrow S=\left \{ x'=-\frac{1}{8}-i\frac{\sqrt{31}}{8},\:x''=-\frac{1}{8}+i\frac{\sqrt{31}}{8} \right \}\\-x^2-x-8=0 \Rightarrow S=\left\{\quad x'=-\frac{1}{2}-i\frac{\sqrt{31}}{2},\:x''=-\frac{1}{2}+i\frac{\sqrt{31}}{2} \right \}\\x^2-x+30=0\Rightarrow S=\left \{ x'=\frac{1}{2}+i\frac{\sqrt{119}}{2},\:x''=\frac{1}{2}-i\frac{\sqrt{119}}{2} \right \}\\(...)

2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

x^5\:-\:x^4\:+\:x^3\:-\:x^2\:-\:12x\:+\:12=0 \Rightarrow S=\left \{ x_{1}=1,\:x_{2}=-\sqrt{3},\:x_{3}=\sqrt{3},\:x_{4}=2i,\:x_{5}=-2i \right \}\\

4 0
3 years ago
Find the area of the pentagon pictured below.
podryga [215]

Answer:

84.3

Step-by-step explanation:

Google Google Google GoogleGoogle Google Google GoogleGoogle Google Google GoogleGoogle Google Google Google

8 0
4 years ago
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