Answer:
Step-by-step explanation:
-14 + 2x + 3 = 4x - 13 - 7x
We can first add the numbers and coefficients on either side:
2x - 11 = -3x - 13
Then, we can add 3x to both sides:
5x - 11 = -13
We can add 11 to both sides
5x = -13 + 11 = -2
Lastly, we can divide both sides by 5
x = -2 / 5
Given:
The graph of a function and a blue line.
To find:
The correct name for the blue line.
Solution:
Domain: It is the set of inputs. These are the x-values for which the function is defined.
Range: It is the set of outputs. These are the y-values for the function.
Asymptote: The function approaches to a line as x approaches to -∞ or ∞ but not intersect the line, then the line is known as asymptote.
y-intercept: It is the intersection point of the function and the y-axis.
From the given graph it is clear that the function approaches to the blue line as x approaches to -∞ but not intersect the blue line.
So, the blue line is an asymptote of the function.
Look at the graph shown below the blue line represents an asymptote of the graph.
Answer:
C, as q = 62.
Step-by-step explanation:
When you have an equation, your goal is to get the letter you are solving for alone. To do this, you employ a simple rule: what you do to one side of the equals sign, you must do the other.
To isolate q in -55 + q = 7, you must add 55 to the left side. q is now alone. However, because we added 55 to the left side, we must also do it to the right! 7 + 55 = 62, so the new right side is 62. Hence, we get to this:
q = 62
The answer is now in plain sight!
I’m pretty sure it’s 43.96 I may be wrong though!
The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 =
{-5, 3}
