All categories

3 years ago

What's 67% as a decimal?

Mathematics

2 answers:

Tems11 [23]3 years ago

8 0

67% as a decimal is actually 0.67.

I hope this answered your question correctly.

WARRIOR [948]3 years ago

7 0

0.67, because when you have a percent like that you just need to move the decimal 2 places to the left.

You might be interested in

Two hikers stopped for a snack. They shared 2/3 of a pound of trail mix. If the hikers shared the trail mix equally, how much tr

allochka39001 [22]

each hiker gets 1 1/2

i hope this helped

5 0

3 years ago

Read 2 more answers

Help me<br><br> g + 3 + 4(9 + 2) =

GrogVix [38]

Answer:

g+3 +36+8=

g+39+8=

g+47

You can't find an answer but this is how you would simplify it :)

Step-by-step explanation:

4 0

3 years ago

I need help with this

zhenek [66]

Answer:

6 1/5 = 31/5 and 2 3/4 = 11/4 as improper fractions, hope this helps!

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The scatter plot shows a regression line of advertising dollars spent and sales. If the company were to spend $275,000 on advert

Misha Larkins [42]

Answer: need the graph please

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

3 years ago