I have no formula however the process would be erosion... copper is a type of metal and when it rots from water or any type of liquid damage it erodes and gets that green coat.
Answer:
93.15 %
Explanation:
We have to start with the chemical reaction:
Now, we can balance the reaction:
Our initial data are the 15.71 g of 
, so we have to do the following steps:
1) <u>Convert from grams to moles of using the molar mass (110.98 g/mol).</u>
2) <u>Convert from moles of to moles of 
using the molar ratio. ( 1 mol = 1 mol of ).</u>
3) <u>Convert from moles of to grams of using the molar mass. (100 g/mol).</u>
Finally, we can calculate the yield percent:
I hope it helps!
Answer:
76.25cm
Explanation:
38cm + 56cm +97cm +114cm = 305cm
305cm÷4 = 76.25cm
Answer:
Ag₂CrO₄(s) + H⁺(aq) ⟶ 2Ag⁺(aq) + HCrO₄⁻(aq)
Explanation:
Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + CrO₄²⁻(aq).
Silver chromate is the salt of a strong base (AgOH) and a weak acid (H₂CrO₄).
HCrO₄⁻ is an even weaker acid than H₂CrO₄, so CrO₄²⁻ is a strong base.
Any added H⁺ will immediately combine with the chromate ions according to the reaction
H⁺ + CrO₄²⁻ ⟶ HCrO₄⁻
thereby removing chromate ions from solution.
According to Le Châtelier's Principle, more silver chromate will dissolve to replace the chromate ions that the H⁺ removes.
The overall equation for the reaction is
Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + <em>CrO₄²⁻(aq)
</em>
<u>H⁺(aq) + </u><em><u>CrO₄²⁻(aq)</u></em><u> ⟶ HCrO₄⁻(aq)
</u>
Ag₂CrO₄(s) + H⁺(aq) ⟶ 2Ag⁺(aq) + HCrO₄⁻(aq)
