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maks197457 [2]
3 years ago
6

Give an example of how microorganisms might meet each of the challenges of life

Chemistry
1 answer:
VikaD [51]3 years ago
7 0
An example would be that they can reproduce just like anything else that is living
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SOMEONE PLS HELP
Gekata [30.6K]

Answer:

<h2>464.85 mL</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we're finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

100.7 kPa = 100,700 Pa

95.1 kPa = 95,100 Pa

We have

V_2 =  \frac{100700 \times 439}{95100}  =  \frac{44207300}{95100}  \\  = 464.8506...

We have the final answer as

<h3>464.85 mL</h3>

Hope this helps you

6 0
3 years ago
Explain why the electron configuration of 2-3-1 represents an atom in an excited state?
baherus [9]

Answer:

See explanation

Explanation:

If we look at the electron configuration closely, we will discover that the element must have had a ground state electron configuration of 2,4.

This is because, the innermost shell usually holds two electrons while the outer shells hold eight electrons each. The four electrons must be accommodated in the second shell in the ground state configuration of the compound.

However, when the atom is excited, one electron from this shell may move to the third shell to give the excited state configuration 2-3-1 as shown in the question.

6 0
3 years ago
In a motion diagram the size of the object must be less than the distance moved t or f
KATRIN_1 [288]
The awnser is false.
6 0
3 years ago
Read 2 more answers
Why would methane attain a tetrahedral structure?​
lys-0071 [83]

<h2>HOPE THIS HELPS YOU ....</h2><h3>PLEASE MARK ME AS BRAINILIST...</h3>

3 0
3 years ago
Read 2 more answers
A 2.912 g sample of a compounds containing only C, H, and O was completely oxidized in a reaction that yielded 3.123 g of water
Taya2010 [7]

Answer:

Explanation:

18 gram of water contains 2 g of hydrogen

3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .

44 gram of carbon dioxide contains 12 g of carbon

7.691 gram of carbon dioxide will contain 12 x 7.691 / 44 = 2.1 g of carbon .

So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .

= .465 g of oxygen .

moles of Carbon = 2.1 / 12 = .175

moles of hydrogen = .347 / 1 = .347

moles of oxygen = .465 / 16 = .029

Ratio of moles of carbon , oxygen and hydrogen ( C,O,H )

= 0.175 : 0.029 : 0.347

= .175/ .029 : 1 : .347 / .029

= 6 : 1 : 12

So empirical formula = C₆H₁₂O

Let the molecular formula be (C_6H_{12}O)_n

molecular weight = n ( 6 x 12 + 12x 1 + 16)

= 100 n

Given 100 n = 100.1

n = 1

Molecular formula = C₆H₁₂O.

3 0
3 years ago
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