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natulia [17]
3 years ago
14

which factor would increase the carrying capacity for a white-tailed deer in an eastern temperate forest ecosystem

Chemistry
2 answers:
ycow [4]3 years ago
6 0

Answer:

<u>Development of natural reserves of forest land and crack down on hunting</u>

Explanation:

  • White-tailed deer also known as Virginia deer is a small to medium-sized deer common to North America, and South America. Deer coat is reddish-brown in spring and summer they turn grey-brown through the fall in winter.
  • A resident of the temperate grasslands adapted themselves to open lands of prairie, and savanna woodlands. They commonly eat leguminous crops and forge on other crops including leaves, cacti, and shoots. They also eat acorns, fruit, and corn.  
  • Due to climate change and the influence of man majority of deer have migrated and the impact of diseases has also reduced the large deep population which can be overcome by rehabilitation programs so as their original habitats are ensured.
saveliy_v [14]3 years ago
4 0
This is a guess, but I think it could be the lack of limiting factors.
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How many kilograms of solvent would contain 0.43 mol of CaO in a 2.5 molality solution
dalvyx [7]
<h3>Answer:</h3>

0.024 kg CaO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.41 mol CaO

2.5 M Solution

<u>Step 2: Identify Conversions</u>

1000 g = 1 kg

Molar Mass of Ca - 40.08 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 0.43 \ mol \ CaO(\frac{56.08 \ g \ Cao}{1 \ mol \ CaO})(\frac{1 \ kg \ CaO}{1000 \ g \ CaO})
  2. Multiply:                              \displaystyle 0.024114 \ kg \ CaO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

0.024114 kg CaO ≈ 0.024 kg CaO

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