Answer:
(a) 3.75
(b) 2.00083
(c) 0.4898
Step-by-step explanation:
It is provided that X has a continuous uniform distribution over the interval [1.3, 6.2].
(a)
Compute the mean of X as follows:
(b)
Compute the variance of X as follows:
(c)
Compute the value of P(X < 3.7) as follows:
![P(X < 3.7)=\int\limits^{3.7}_{1.3}{\frac{1}{6.2-1.3}}\, dx\\\\=\frac{1}{4.9}\times [x]^{3.7}_{1.3}\\\\=\frac{3.7-1.3}{4.9}\\\\\approx 0.4898](https://tex.z-dn.net/?f=P%28X%20%3C%203.7%29%3D%5Cint%5Climits%5E%7B3.7%7D_%7B1.3%7D%7B%5Cfrac%7B1%7D%7B6.2-1.3%7D%7D%5C%2C%20dx%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B4.9%7D%5Ctimes%20%5Bx%5D%5E%7B3.7%7D_%7B1.3%7D%5C%5C%5C%5C%3D%5Cfrac%7B3.7-1.3%7D%7B4.9%7D%5C%5C%5C%5C%5Capprox%200.4898)
Thus, the value of P(X < 3.7) is 0.4898.
The simplified answer would be 9120ax
88 minutes (1 hour and 28 mins)
Since 5 miles takes 40 minutes, multiplying both numbers by 2 gets you to 10 miles in 80 minutes. To get the extra 1 more miles you have to find the unit rate
5 miles in 40 minutes : divided both numbers by 5 to get
1 mile in 8 minutes
add the one mile in 8 minutes to the 10 miles in 80 mins and you get 11 miles in 88 minutes
The population of the fish is given by P(t) = 750(1 + 0.083)^t; where t is the number of years after 2005.
Here, t = 2050 - 2005 = 45
Population in 2050 = 750(1.083)^45 = 750(36.16) = 27,123
6+z=10x-2
6+z=-20
Z=-20-6
Z=-26
Hope this helps!
