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laila [671]
3 years ago
13

Simplify 2/√3-√2 Simplify √15b^5/25

Mathematics
1 answer:
Scrat [10]3 years ago
4 0
2/ (√3-√2)=2(√3+√2) / (√3-√2)(√3+√2)=2(√3+√2) / (3-2)=2(√3+√2)

√(15 b⁵/25)=b²√(3b/5)
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What is the value of 8/3 squared in a fraction
love history [14]
The answer would be 64/9. I did this by squaring each number so 8^2 and 3^2 should give me 8*8 which is 64 and 3*3 which is 9. I hope this helped you!
5 0
4 years ago
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An initial investment of $60.00 increases in value by 15% each year. Which of the following statements are true? Select all that
VikaD [51]
15% each yer
represented by
f(x)=60(1.15^x)

xintercept is when the function equals zero
since it increases only, it cannot equal zero and does not have an x intercept

after 4 years the investment value is 104
after 6 yaers value is 138.7
after 7.86 years the value is179.98 which is roughly 3 times of 60
8 years later183.54 close enough










answers
f(x)=60*1.15^x
after 7.86 years value is 3 times initioal value
after 8 years value is 184

4 0
4 years ago
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8(1/2u+3/4)
netineya [11]

Answer:

4u+3

Step-by-step explanation:  8/1*1/2= 8/2=4u

                                              8/1*3/4= 24/8=3    

4 0
3 years ago
Help i have no idea how to solve this
ASHA 777 [7]

Answer:

AB =24

Step-by-step explanation:

So, since all the sides are equal, you can just take two of the sides and set em equal to each other to find x and then, solve for AB

4x+8 =6x

8= 6x-4x

8=2x

8/2 =x

x= 4

Now, find AB, which is 4x+8

4(4) + 8

16+8 = 24

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

5 0
3 years ago
What is the radius of a circle with the equation x^2+y^2+6x-2y+3?
atroni [7]

Answer:

r = √13

Step-by-step explanation:

Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms:  x^2 + 6x            + y^2 -2y             = 3.  Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."  

We need to "complete the square" of x^2 + 6x.  I'll just jump in and do it:  Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x:     x^2 + 6x  + 3^2 - 3^2.  Then do the same for y^2 - 2y:  y^2 - 2y + 1^2 - 1^2.

Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2.  Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1.  Making these replacements:

(x + 3)^2 - 9 + (y - 1)^2 -1 = 3.  Move the constants -9 and -1 to the other side of the equation:  (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13

Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r:  r^2 = 13, so that the radius is r = √13.


8 0
3 years ago
Read 2 more answers
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