Plz help..................

Which represents the solution set of an any quality 5X-9 greater than 21

Svet_ta [14]

Answer:

The last one

Step-by-step explanation:

5x<30

x<6

Because when you divide by pos+ number

the symbol cannot change.

6 0

3 years ago

What is the caputal of idaho

zavuch27 [327]

Capital of Idaho is boise this is not a math question

5 0

3 years ago

Read 2 more answers

What number is equivilent to 3 4/ 3 2

ki77a [65]

Answer:

9

Step-by-step explanation:

Using the property that

a

m

a

n

=

a

m

−

n

, we have

3

4

2

=

3

4

−

2

=

3

2

=

9

Note that if we evaluated the numerator and denominator first, we would arrive at the same result:

3

4

3

2

=

81

9

=

9

8 0

3 years ago

Read 2 more answers

The table shows the relationship

Airida [17]

The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0

Change in weight per day of hibernation = - 0.03
Change in weight for 115 days = - 3.45 ounces

A linear model can be created using the data in the table given using a regression calculator or excel ;

The linear model obtained in the form y = m + bx is :

y = - 0.03x + 0
y = change in weight
x = number of days of hibernation
Intercept = 0
Slope = -0.03

The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.

Using the regression equation, substitute, the vlaue of x = 115
-0.03(115) + 0 = - 3.45

Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.

Learn more :brainly.com/question/18405415

8 0

2 years ago

Several years ago, 38% of parents who had children in grades K-12 were satisfied with the quality of education the students r

Colt1911 [192]

Answer:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values are:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The estimated proportion of people satisfied with the quality of education the students receive is given by:

$\hat p =\frac{499}{1165}= 0.428$

The confidence interval for the proportion if interest is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing the info given we got:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0

3 years ago