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Anit [1.1K]
2 years ago
14

Can someone help me?

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
4 0
I’m sorry I can’t see it well enough (my eyesight is bad)
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I NEED HELP !!!!!!!!!
marissa [1.9K]

Answer:

b

d

e

Step-by-step explanation:

the standar form is

ax^{2} +bx+c=0

so it's

0.5x^{2} -3.2x+5.8=0\\\\-x^2-3x+20=0\\\\\frac{1}{2}x^2+4x-3=0\\\\

only that

7 0
3 years ago
please help really simpleeeeeeeeeeeee plsssss help really simple i am just checking my awnser pease tell me what would the coord
Furkat [3]

Answer:

P(-1, 0); Q(0, -1); R(2, -1).

Step-by-step explanation:

When you reflect coordinates over the y-axis, the y-coordinates do not change, while the signs of the x-coordinates are flipped. You can see the example attached!

And so, after reflecting P'(1, 0), you would get P(-1, 0) because the sign of the x-value is flipped and the y-value does not change.

Q'(0, -1) becomes Q(0, -1) because 0 is neither negative nor positive, and the y-value does not change.

R'(-2, -1) becomes R(2, -1) because the sign of the x-value is flipped to positive and the y-value does not change.

Hope this helps!

4 0
3 years ago
write a polynomial function of least degree with integral coefficients having zeros that include -1 and 1 + 2i
SOVA2 [1]

Answer:

Step-by-step explanation:

hello :

a polynomial function is:

f(x) = a (x+1)(x-1)(x-2i)    .... a ≠ 0

7 0
3 years ago
Please help me on this will give you brainliest
enyata [817]

Answer:

135 x 10^7

Step-by-step explanation:

27(5 x 10^7)

probably check before turning in

7 0
3 years ago
Evaluate tan(Sin-1(-5/13)). Answer as a fraction please.
dangina [55]

Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))

Let A = arcsin(-5/13) = -arcsin(5/13)

Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0
3 years ago
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