Answer:5.5
Step-by-step explanation:
2y-9=-2
+9 +9
2y/2 = 11/2
5.5
Given:
A rectangle has a length 5 meters more than five times the width.
The area of the rectangle is less than 100 meters squared.
To find:
The expression or inequality that represents all possible widths of the rectangle.
Solution:
Let x be the width of the rectangle.
Length of the rectangle is 5 meters more than five times the width.
![length=5x+5](https://tex.z-dn.net/?f=length%3D5x%2B5)
Area of rectangle is
![Area=length \times width](https://tex.z-dn.net/?f=Area%3Dlength%20%5Ctimes%20width)
![Area=(5x+5) \times x](https://tex.z-dn.net/?f=Area%3D%285x%2B5%29%20%5Ctimes%20x)
![Area=5x^2+5x](https://tex.z-dn.net/?f=Area%3D5x%5E2%2B5x)
The area of the rectangle is less than 100 meters squared.
![5x^2+5x](https://tex.z-dn.net/?f=5x%5E2%2B5x%3C100)
![5x^2+5x-100](https://tex.z-dn.net/?f=5x%5E2%2B5x-100%3C0)
Divide both sides by 5.
![x^2+x-20](https://tex.z-dn.net/?f=x%5E2%2Bx-20%3C0)
![x^2+5x-4x-20](https://tex.z-dn.net/?f=x%5E2%2B5x-4x-20%3C0)
![x(x+5)-4(x+5)](https://tex.z-dn.net/?f=x%28x%2B5%29-4%28x%2B5%29%3C0)
![(x+5)(x-4)](https://tex.z-dn.net/?f=%28x%2B5%29%28x-4%29%3C0)
It is true if one factor is negative and other is positive. So,
...(i)
...(ii)
Using (i) and (ii), we get
![-5](https://tex.z-dn.net/?f=-5%3Cx%3C4)
Therefore, the required expression or inequality for possible
widths of the rectangle is
.
Since 7 - 3 is in parentheses, I will subtract that first, giving me 4. Next, I divide 11 and 4. 11 / 4 = 2.75
Answer:
x - 7
Step-by-step explanation:
x + 8 - 15
Subtract 15 - 8 = 7
x - 7
<u><em>~Lenvy~</em></u>
Answer: OE
Step-by-step explanation: This is the only relationship in which one variable impacts the other