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Anit [1.1K]
3 years ago
14

Can someone help me?

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0
I’m sorry I can’t see it well enough (my eyesight is bad)
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A home has a triangular backyard. The second angle of the triangle is 4degrees more than the first angle. The third angle is 8de
amid [387]

Answer:

1st angle = X

2nd angle = X + 7

3rd angle = X + 18

Then (sum. them): 3X + 25 = 180   ==>  X = 51.67 degree

Therefore,

1st angle = 51.67 degree

2nd angle = 58.67 degree

3rd angle = 69.67 degree

5 0
3 years ago
Read 2 more answers
The sequence a1, a2, a3, . . . , an of n integers is such that ak = k if k is odd and ak = –ak – 1 if k is even. Is the sum of t
nasty-shy [4]

Answer:

Step-by-step explanation:

The

5 0
3 years ago
Given:  m∠p =47BD∥AC <br> What is the m∠m?<br><br> Put only the number. Do not label your answer.
Anettt [7]

Answer: 43\°

Step-by-step explanation:

Observe the given figure.

You can identify that the measure of the angle "B" is:

m\angle B=90\°

Knowing this, you can conclude that the angle "p" and the angle "m" are Complementary angles, which means that the sum of their measures is 90 degrees. Then, you can write the following equation:

m\angle p+m\angle m=90\°   [Equation 1]

You know that:

m\angle p=47\°

Then you can substitute it into the [Equation 1] and then solve for m\angle m. Therefore, you get:

 47\°+m\angle m=90\°\\\\m\angle m=90\°-47\°\\\\m\angle m=43\°

3 0
3 years ago
Round 0.83,to the nearest thousandths<br> NEED HELP IMMEDIATELY!!!
Dafna1 [17]
0.008 i think this is the answer
5 0
3 years ago
What is the equation, in standard form, of a parabola that models the values in the table?
love history [14]

Answer:

<u>Y=4x^2+3x-6</u>

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

<u>Y=3x^2+4x-6 for (-2,4)</u>

Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\

This does not give 4 as the answer and is not a solution.

<u>Y=4x^2+3x-6 for (-2,4)</u>

Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\

This does give 4 as the answer and is a possible solution.

<u>Y=4x^2-3x-6 for (-2,4)</u>

Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\

This does not give 4 as the answer and is not a solution.

<u>Y=-4x^2-3x-6 for (-2,4)</u>

Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\

This does not give 4 as the answer and is not a solution.

The only possible solution is <u>Y=4x^2+3x-6</u>

3 0
3 years ago
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