We are given the function <span>f(x)=sqrt of (4sinx+2) and is asked to find the first derivative of the function when x is equal to zero.
</span><span>f(x)=sqrt of (4sinx+2)
f'(x) = 0.5 </span><span>(4sinx+2) ^ -0.5 * (4cosx)
</span>f'(0) = 0.5 <span>(4sin0+2) ^ -0.5 * (4cos0)
</span>f'(0) = 0.5 <span>(0+2) ^ -0.5 * (4*1)
</span>f'(x) = 0.5 (2) ^ -0.5 * (4)
f'(x) = -.1.65
4 for the first one and 1.5 for the second one
Ok what do you need help with
Answer:
You can conclude from the diagram that m∠P is less than m∠N ⇒ A
Step-by-step explanation:
- In any triangle, you can arrange the lengths of the sides according to the measure of the opposite angles
- In any triangle, you can arrange the measure of the angles according to the lengths of the opposite sides
<u><em>Example:</em></u>
In ΔABC, if the arrangement of the sides is AB < BC < CA, then the arrangement of the measures of the angles is m∠C < m∠A < m∠B
Let us use this fact to solve the question
→ In ΔKNP
∵ KP = 8 units
∵ KN = 6 units
∵ 6 < 8
∴ KN < KP
∵ ∠P is opposite to the side KN
∵ ∠N is opposite to the side KP
∵ KN < KP
→ By using the fact above
∴ m∠P < m∠N
∴ m∠P is less than m∠N
∴ You can conclude from the diagram that m∠P is less than m∠N
Answer:
Step-by-step explanation:
plz can someone help me
