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qaws [65]
3 years ago
10

Help identify BD in terms of TT

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0
arc \ length \ of \ BD = \pi r ( \frac{\angle BPD}{180} )  \\  \\ \angle BPD=\angle APC=92^o \ \ \text{[vertical angle]} \\  \\ arcBD= \pi *8 *\frac{92}{180}  \approx 4.09 \pi  \ in \approx12.85 in


Answer: ≈4.09π in. ≈12.85 in.
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irakobra [83]

Step-by-step explanation:

-9x-4y=1....eq1

3x+3y=3.....eq2

multiply eq2 by 3

to get

9x+9y=9....eq3

add eq1 and 3

0+5y=10

5y=10

divide both sides by 5

y=2

substitute y=2 in to eq1

-9x-4(2)=1

-9x-8=1

grouping of like terms

-9x=1+8

-9x=9

divide both sides by -9

x= -1

now the answer is

x= -1, y=2

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3 years ago
Whats an outlier?
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Answer:

In statistics, an outlier is a data point that differs significantly from other observations.

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Which fractions use the least common denominator and are equivalent to 9/10 and 5/6
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4 years ago
Find the measure of angle A
Salsk061 [2.6K]

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----------------------

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4 0
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Read 2 more answers
If the measure of angle BCD=51 degrees, solve for x.
BabaBlast [244]

Answer:

x=5

Step-by-step explanation:

step 1

Find the measure of angle EFD

In this problem I will assume that ABCD is a parallelogram

In a parallelogram opposite angles are congruent and consecutive angles are supplementary

so

m\ angle BCD=m\angle BED=51^o

m\ angle FED=(1/2)m\angle BED=(1/2)51^o=25.5^o --- > given problem

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

In the triangle EFD

m\ angle FED+m\ angle FDE+m\ angle EFD=180^o

substitute the given values

25.5^o+55^o+m\ angle EFD=180^o

80.5^o+m\ angle EFD=180^o

m\ angle EFD=180^o-80.5^o

m\ angle EFD=99.5^o

step 2

Find the measure of angle EFB

we know that

m\angle EFB+m\angle EFD=180^o ---> by supplementary angles

we have

m\ angle EFD=99.5^o

substitute

m\angle EFB+99.5^o=180^o

m\angle EFB=180^o-99.5^o

m\angle EFB=80.5^o

step 3

Find the value of x

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

In the triangle EBF

m\ angle BEF+m\ angle EFB+m\ angle EBF=180^o

we have

m\angle BEF=m\ angle FED=25.5^o

m\angle EFB=80.5^o

m\angle EBF=(14x+4)^o

substitute

25.5^o+80.5^o+(14x+4)^o=180^o

solve for x

Combine like terms

(14x+110)^o=180^o

14x=180-110

14x=70

x=5

4 0
3 years ago
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