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Masja [62]
3 years ago
12

In the figure, lines a, b, and c are parallel and m∠4=156° . Drag and drop the correct angle measure for each angle.

Mathematics
2 answers:
lutik1710 [3]3 years ago
6 0
Those are the perfect answer
well done:)

but please <span>Brainliest mark me as the answer and thank me
and all the best</span>
gayaneshka [121]3 years ago
6 0

Answer:

m

m

m

m

Step-by-step explanation:

Part 1) If line a is parallel to line b

then

m -----> by alternate exterior angles

so

we have

m

therefore

m

Part 2) we know that

m -----> by supplementary angles

we have

m

substitute

156\°+m

m

Part 3) If line a is parallel to line b

then

m -----> by alternate interior angles

so

we have

m

therefore

m

Part 4) If line b is parallel to line c

then

m -----> by corresponding angles

so

we have

m

therefore

m

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1.Find the area of a trapezium with parallel sides of
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Answer:

The area of the trapezium is 74.8\ cm^2

Step-by-step explanation:

Area of a trapezium:

\displaystyle A=\frac{b1+b2}{2}h

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Since the trapezium given in the problem satisfies those conditions, we use the formula with:

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Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
mariarad [96]

Answer:

a) 0.1587 (or 15.87%)

b) 0.0478 (or 4.78%)

c) 0.7935 (or 79.35%)

Step-by-step explanation:

Find the following probabilities:

(a) the thickness is less than 3.0 mm

We need to find the area under the Normal curve with a mean of 4.5 mm and a standard deviation of 1.5 mm to the left of 3 mm

<h3>(See picture 1 attached) </h3>

We can do that with the help of a calculator or a spreadsheet.

<em>In Excel use </em>

<em>NORMDIST(3,4.5,1.5,1) </em>

<em>In OpenOffice Calc use  </em>

<em>NORMDIST(3;4.5;1.5;1) </em>

and we get the value 0.1587 (or 15.87%)

(b) the thickness is more than 7.0 mm

Now we need the area to the right of 7 (1 - the area to the left of 7)

<h3>(See picture 2 attached) </h3>

<em>In Excel use </em>

<em>1-NORMDIST(7,4.5,1.5,1)  </em>

<em>In OpenOffice Calc use  </em>

<em>1-NORMDIST(7;4.5;1.5;1) </em>

and we get the value 0.0478 (or 4.78%)

(c) the thickness is between 3.0 mm and 7.0 mm

We are looking for the area between 3 and 7

<h3>(See Picture 3) </h3>

Since the area under the Normal equals 1, we have

Area to the left of 3 + Area between 3 and 7 + Area to the right of 7 = 1

Hence,  

0.1587 +  Area between 3 and 7 + 0.0478 = 1

and

Area between 3 and 7 = 1 - 0.1587 - 0.0478 = 0.7935 (or 79.35%)

4 0
3 years ago
Read 2 more answers
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