Answer:
Circular paraboloid
Step-by-step explanation:
Given ,

Here, these are the respective
axes components.
- <em>Component along x axis
</em>
- <em>Component along y axis
</em>
- <em>Component along z axis
</em>
We see that , from the parameterised equation , 
This can also be written as :

This is similar to an equation of a parabola in 1 Dimension.
By fixing the value of z=0,
<u><em>We get
which is equation of a parabola curving towards the positive infinity of y-axis and in the x-y plane.</em></u>
By fixing the value of x=0,
<u><em>We get
which is equation of a parabola curving towards positive infinity of y-axis and in the y-z plane. </em></u>
Thus by fixing the values of x and z alternatively , we get a <u>CIRCULAR PARABOLOID. </u>
Answer:
Choose f(x) = 11x + 1
Step-by-step explanation:
Note that we will simply plug the value of 2 into the equation for February:
f(2) = 11(2) + 1 = 23
And plug the value of 6 into the equation for June:
f(6) = 11(6) + 1 = 67
Note how the points on the graph seem to match up with these values. If we evaluate following the same style for each:
f(3) = 11(3) + 1 = 34
f(4) = 11(4) + 1 = 45
f(5) = 11(5) + 1 = 56
Note, these values seems to be very close in approximation to the graph points for each month.
The other three functions return values that are just to far away from what are represented in the graph.
Cheers.
Answer:
4√5
Step-by-step explanation:
Use Pythagorean theorem
a^2=21^2-19^2
a^2=441-19^2
a^2=441-361
a^2=80
a= √80
simplify